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jeyben [28]
3 years ago
7

What is an equation of the line that passes through the points (-3,8) and (4,1)?

Mathematics
1 answer:
GuDViN [60]3 years ago
6 0

Answer: y= -1x + 5

Step-by-step explanation:

(-3,8) ( 4,1)

8-1= 7

-3-4 = -7

7/-7 = -1  so the slope is -1   so we will use the formula y=mx+b to find the y-intercept

8= -1(-3) + b

8= 3 + b

-3   -3

b= 5  so the y intercept is 5 now we will write the equation like this y= -1x + 5

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charle [14.2K]

Answer:

\boxed{(f + g)(x) = {x}^{2} - x + 6}

Given:

f(x) =  {x}^{2}  + 1 \\  \\ g(x) = 5 - x

To Find:

(f + g)(x) = f(x) + g(x)

Step-by-step explanation:

=  > f(x) + g(x) =  ({x}^{2}  + 1) + (5 - x) \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = {x}^{2}  + 1 + 5 - x\\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = {x}^{2}  + 6 - x\\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = {x}^{2} - x + 6

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