In the isosceles trapezoid ABCD, draw two perpendiculars AM and BL from A and B to the side CD.
Now, LM = BA = 5 m
CD = CL + LM + MD
= CL + 5 + CL (CL = MD)
= 2CL + 5
But, CD = 11
Therefore, 2CL + 5 = 11
2CL = 11 - 5
= 6
CL = 6/2 = 3m
MD = 3m
Now, consider the right triangle AMD.
We have,

= 
= 16 - 9
= 7
Hence, height of the isosceles trapezoid = AM = 
Answer:
TSA = 88
Step-by-step explanation:
Formula we use,
→ TSA = 2(lb + bh + lh)
The TSA of rectangular prism will be,
→ 2(lb + bh + lh)
→ 2[(6 × 4) + (4 × 2) + (6 × 2)]
→ 2(24 + 8 + 12)
→ 2 × 44 = 88
Hence, the TSA is 88.
Answer:
C. xy⁵ ³√xy
Step-by-step explanation:
The vertex is when x=-b/2a
in this case, b=-8, a=-1, so x=-(-8)/2(-1)=-4
when x=-4, y=-(-4)²-8(-4)+2=18
so the answer is B.