Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
-14 - 12i
Step-by-step explanation:
Apply complex arithmetic rule: (ai)(b + ci) = -ac + abi
a = 2, b = 6, c = -7
-( -2(-7) + 2*6i )
-( 14 + 12i)
-14 - 12i
Factor is it because the numbers begin multiplied are called factor so it will be 3x a factor
Answer:
C
=
(
a
,
b
)
the center coordinates of circle
a
=
2
,
b
=
−
1
,
r
=
8
Step-by-step explanation:
Hi,
To find the number of small cylinders that fit inside the big cylinder. You need to divide volume of small cylinder with the volume of big cylinder. We do this by using formula to calculate volume of cylinder:

To find radius just divide diameter with 2.

Now just division:

Answer: You could fit 374.8 smaller cylinders inside a big cylinder.
Hope this helps.
r3t40