Step-by-step explanation:
so we're making two draws *with* replacement (this is important)
step 1: for the first draw, it wants the probability of getting a sour candy. to calculate this:
(# of sour candy) / (total # of candy)
step 2: for the second draw, it wants the probability of *not* getting a sour candy. to calculate this, you can calculate 1 - (the probability form part 1).
step 3: to find the probability of both events happening together, simply multiply the probabilities from part 1 and 2 together
side note: for step 2, you can only do this because the candy is being replaced. if there were no replacement, you'd have to re-calculate (# of non-sour candies) / (total after the first candy is drawn)
Step-by-step explanation:
Number of males is
Number of males not enrolled
Number of females not enrolled
(a)
The table based on data is
<u> Enrolled Not enrolled Total </u>
<u>Male 82 36 118 </u>
<u>Female 102 56 158 </u>
Total 184 92 276
(b)
Percentage of students were males that went to magic college
- enrolled male / total students = (use table above)
- 82/276*100% = 29.71% (rounded)
(c)
Percentage of females went to magic college
- enrolled female / total female = (use table above)
- 102/158*100% = 64.56% (rounded)
<span>given:
bull's eye radius= x
width of surrounding rings=y
solution:
Radius of the circle=x+4y
Area of the outermost ring=Area of the circle-Area of the penultimate ring
=Ď€(x+4y)^2-Ď€(x+3y)^2
=Ď€(x^2+8xy+16y^2-x^2-9y^2-6xy)
=Ď€(2xy+7y^2)
hence the area of the outermost ring in terms of x and y is π(2xy+7y^2).</span>
