It number four
This
H
Yehjehw Kenzie
-38382822
Hello!
The answer is:
Luke did a work of 308N.m or 308 Joules.
<h2>
Why?</h2>
When a force is applied on a object making it to move covering a distance we call it "work". The movement caused by the force, will follow the same direction that the force.
We can calculate the work done by using the following equation:

Where,
Work is the transferred energy.
Force, is the force applied to the object.
Distance, is the distance covered due to the applied force.
α, is the angle at the work is done.
We are given the following information to calculate the work done:

So, substituting the given information into the equation to calculate work, we have:

Hence, we have that Luke did a work of 308N.m or 308 Jouls.
Have a nice day!
Answer:
7.375 ib.
Step-by-step explanation:
You just add it all together
Answer:
u = 12, v= 15
Step-by-step explanation:
Given the system of simultaneous equation:
1/6 u− 1/3 v=−3... (1)
0.2u+0.1v=3.9...(2)
Rewriting both equation as fraction
1/6 u− 1/3 v=−3
1/5 u + 1/10 v = 39/10
Multiplying equation (1) by 6 and (2) by 10 we have:
u - 2v = -18... (3)
2u + v = 39...(4)
Using elimination method, we will first multiply equation (3) by 2 and (2) by 1 to have:
2u-4v = -36 ...(5)
2u+v = 39...(6)
Subtracting (5) from (6);
-4v-v = -36-39
-5v = -75
v = -75/-5
v = 15
Substituting v = 15 into equation (3) to get u we have:
u - 2(15) = -18
u - 30 = -18
u = -18+30
u = 12
The solution to the system of simultaneous equation are u = 12 and v = 15