Well maybe because the only thing that is different is the - and +
Answer:
a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

d.9
b) 
a.15
c) For this case we have the sample size n = 25 and the sample variance is
, the standard error can founded with this formula:

Step-by-step explanation:
Part a
For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

d.9
Part b
From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

And the sample variance for this case can be calculated from this formula:

a.15
Part c
For this case we have the sample size n = 25 and the sample variance is
, the standard error can founded with this formula:

Answer:
-26
Step-by-step explanation:
5p + (-6)
Let p=-4
5(-4) + (-6)
Multiply
-20 +-6
Add
-26
Answer:
#16 is linear but idk what 17 is