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3 years ago

7

Straight angle always has 180 degrees this is correct?

1 answer:

sveticcg [70]3 years ago

8 0

Answer:

You are correct

Step-by-step explanation:Nice job have a nice day!!!

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1/3 is equivalent to 3/9

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*URGENT* which answer is a solution to the inequality?

Bad White [126]

Try them and see.

For the first:
3(-3) + 0 = -9 . . . . not > -8
3(-2) + (-1) = -7 . . . is > -8 . . . . . 2) (-2, -1) is a solution

For the second:
4 - 4(-2) = 12 . . . . not ≤ -6
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2 years ago

AB is the angle bisector find x

bixtya [17]

Answer:

x=9

Step-by-step explanation:

2(x-1)=3x-11

distribute the 2

subtract 2x from both sides and get -2=x-11

add 11 to both sides and get x=9

6 0

2 years ago

Find the moment of inertia about the y-axis of the thin semicirular region of constant density

arlik [135]

The moment of inertia about the y-axis of the thin semicircular region of constant density is given below.

$\rm I_y = \dfrac{1}{8} \times \pi r^4$

<h3>What is rotational inertia?</h3>

Any item that can be turned has rotational inertia as a quality. It's a scalar value that indicates how complex it is to adjust an object's rotational velocity around a certain axis.

Then the moment of inertia about the y-axis of the thin semicircular region of constant density will be

$\rm I_x = \int y^2 dA\\\\I_y = \int x^2 dA$

x = r cos θ

y = r sin θ

dA = r dr dθ

Then the moment of inertia about the x-axis will be

$\rm I_x = \int _0^r \int _0^{\pi} (r\sin \theta )^2 \ r \ dr \ d\theta\\\\\rm I_x = \int _0^r \int _0^{\pi} r^3 \sin ^2\theta \ dr \ d\theta$

On integration, we have

$\rm I_x = \dfrac{1}{8} \times \pi r^4$

Then the moment of inertia about the y-axis will be

$\rm I_y = \int _0^r \int _0^{\pi} (r\cos\theta )^2 \ r \ dr \ d\theta\\\\\rm I_y = \int _0^r \int _0^{\pi} r^3 \cos ^2\theta \ dr \ d\theta$

On integration, we have

$\rm I_y = \dfrac{1}{8} \times \pi r^4$

Then the moment of inertia about O will be

$\rm I_o = I_x + I_y\\\\I_o = \dfrac{1}{8} \times \pi r^4 + \dfrac{1}{8} \times \pi r^4\\\\I_o = \dfrac{1}{4} \times \pi r^4$

More about the rotational inertia link is given below.

brainly.com/question/22513079

#SPJ4

3 0

1 year ago