Ask question

Ask question

All categories

3 years ago

7

Need help ASAP ( frist one branly)!!!!

2 answers:

valentina_108 [34]3 years ago

7 0

Which ones do you need help on?

Lena [83]3 years ago

6 0

At least try to work it out and maybe you'll get it.

You might be interested in

Peter is measuring the growth of a Bush,each year the bush grows 15cm.When he first started measuring the bush,it was only 10cm.

-BARSIC- [3]

Answer:

A

Step-by-step explanation:

I don't know how to explain it.

6 0

3 years ago

Which fraction is equivalent to 9/13?

Doss [256]

9/13 is not a fraction that can be simplified: the two numbers don't have a divisor in common.

Let's bring all the other fractions into their simplest form too:

A.6/10=3/5
B. 2/3 This is the simplest form already
C.36/52 =18/26=9/13 ( I divided both numbers by 2 each time)

.... and we don't have to look further, we have already found the right answer: 9/13 is equivalent to 36/52.

6 0

3 years ago

Use inductive reasoning to find the next term in the sequence 0, 1, 1, 2, 3, 5, 8 … What is the next term?

Anna007 [38]

13, each term is the sum of two preceding ones.

6 0

4 years ago

Which of these choices show a pair if equivelent expressions? Chack all that apply

Gwar [14]

Answer:

A. $(\sqrt[3]{125})^9\ and\ (125)^{\frac{9}{3}}$

D. $8^{\frac{9}{2}}\ and\ (\sqrt{8})^9$

Step-by-step explanation:

Equivalent expressions are those expressions that simplify to same form.

Now, let us check each of the given options.

Option A:

$(\sqrt[3]{125})^9\ and\ (125)^{\frac{9}{3}}$

We know that,

$\sqrt[n]{x} =x^{\frac{1}{n}}$

Therefore, $\sqrt[3]{125} =(125)^{\frac{1}{3}}$

Thus the first expression becomes;

$((125)^{\frac{1}{3}})^9$

Now, using law of indices $(a^m)^n=a^{m\times n}$ , we get

$((125)^{\frac{1}{3}})^9=((125))^{\frac{1}{3}\times 9}=((125))^{\frac{9}{3}$

Therefore, $(\sqrt[3]{125})^9\ and\ (125)^{\frac{9}{3}}$ are equivalent.

Option B:

$12^{\frac{2}{7}}\ and\ (\sqrt{12})^7$

Consider the second expression $(\sqrt{12})^7$

We know that,

$\sqrt x=x^{\frac{1}{2}}$

$(\sqrt{12})^7=((12)^{\frac{1}{2}})^7=(12)^{\frac{1}{2}\times 7}=(12)^{\frac{7}{2}}$

Therefore, $12^{\frac{2}{7}} \ne (12)^{\frac{7}{2}}$ . Hence, the expressions $12^{\frac{2}{7}}\ and\ (\sqrt{12})^7$ are not equivalent.

Option C:

$4^{\frac{1}{5}}\ and\ (\sqrt 4)^5$

We know that,

$x^{\frac{1}{n}}=\sqrt[n]{x}$

Therefore, $4^{\frac{1}{5}}=\sqrt[5]{4}$

Now, $\sqrt[5]{4}\ne (\sqrt 4)^5$

Therefore, the expressions $4^{\frac{1}{5}}\ and\ (\sqrt 4)^5$ are not equivalent.

Option D:

$8^{\frac{9}{2} }\ and\ (\sqrt 8)^9$

Using law of indices $a^{m\times n}=(a^m)^n$ , we get

$8^{\frac{9}{2} }=(8^{\frac{1}{2}})^9$

Now, we know that, $x^{\frac{1}{2}}=\sqrt x$

So, $(8^{\frac{1}{2}})^9=(\sqrt8)^9$

Therefore, $8^{\frac{9}{2} }\ and\ (\sqrt 8)^9$ are equivalent.

8 0

3 years ago

Which of these figures is NOT a quadrilateral?

Anastaziya [24]

A is not a quadrilateral

4 0

3 years ago

Read 2 more answers