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Mazyrski [523]
2 years ago
7

Juanita has a storage closest at her shop with extra bottles of lotion and shower gel. Some are scented and some are unscented.

If she reaches into the closest and grabs a bottle without looking, she has 42% chance of grabbing a bottle of shower gel.
For the events "shower gel" and "scented" to be independent, what must be shown to be true?
Mathematics
2 answers:
Eddi Din [679]2 years ago
7 0
<span>P(shower gel | scented) = 42%</span>
Kisachek [45]2 years ago
7 0

Answer:

The probability of choosing a shower gel given the item is scented must be the same as grabbing shower gel, or 42%.

Step-by-step explanation:

To determine if two events are independent using their probabilities, we look for:

P(A|B) = P(A);

P(B|A) = P(B);

or P(A∩B) = P(A)·P(B)

We know that the probability she chooses a shower gel is 42%.  Letting this be event A, we have:

P(shower gel | scented) = P(shower gel) = 42%

This must be true for the events to be independent.

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Given:

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Number of days he has done the homework = 14

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<u>In October:</u>

Number of days he has done the homework = 14

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<u>In December:</u>

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<u>In July,</u>

The difference between the number of days with homework and with no homework = 6-4 = 2

<u>In August,</u>

The difference between the number of days with homework and with no homework = 16-7 = 9

<u>In September,</u>

The difference between the number of days with homework and with no homework = 14-4 = 10

<u>In October,</u>

The difference between the number of days with homework and with no homework = 14-8 = 6

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The difference between the number of days with homework and with no homework = 16-4 = 12

<u>In December,</u>

The difference between the number of days with homework and with no homework = 10-5 = 5

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In 3 months the difference between the number of days with homework and with no homework greater than 6 and these are: August, September, November.

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