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dexar [7]
3 years ago
12

Which describes the combined variation shown in the equation F= kxy/z ?

Mathematics
2 answers:
DiKsa [7]3 years ago
7 0

Answer:

when the rest of the variables are held constant

Step-by-step explanation:

Stella [2.4K]3 years ago
7 0

Answer:

First question is D: F varies directly with x and y, and inversely with z.

Second Question is B Y=kx^3/sq root z

Edge Verified

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A turtle can walk 1/12 of a kilometer in an hour. The turtle is 1/5 of a kilometer away from a pond. At this speed how long will
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Answer:

2.4 hours

Step-by-step explanation:

Get common denominators -

1/12 x 5/5 = 5/60

1/5 x 12/12 = 12/60

The turtle walks ata 5/60 a kilometer an hour.

divide remaining time by 5/60

(12/60) / (5/60) = 2.4 hours

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Which of the following options represents the graph of the function shown below?
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I think the answer is B but not sure about "11" in A
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Use a matrix to solve the system:
Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\

Rewrite these equations in matrix form

\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\

we can write it like this,

AX=B\\X=A^{-1}B

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]  \\

now multiply the matrix with B

X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\

4 0
3 years ago
An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in t
Natali5045456 [20]

Answer:

a) Kenji's time had a lower z-score, which means that he is better compared to other runners on his level, and better to his peers compared to Nedda.

b) Rachel, because her time had the lowest z-score.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

The lower the time, the better the runner is. So whoever's time has a lower z-score is a better runner. So initially, we find the z-score of each student's time.

An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in the class, ran 1 mile in 8 minutes.

This means that for Rachel's time, we have that X = 8, \mu = 11, \sigma = 3. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 11}{3}

Z = -1

A junior high school class ran 1 mile in an average of 9 minutes, with a standard deviation of 2 minutes. Kenji, a student in the class, ran 1 mile in 8.5 minutes.

This means that for Kenji's time, we have that X = 8.5, \mu = 9, \sigma = 2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.5 - 9}{2}

Z = -0.25

A high school class ran 1 mile in an average of 7 minutes with a standard deviation of 4 minutes. Nedda, a student in the class, ran 1 mile in 8 minutes.

This means that for Nedda's time, we have that X = 8, \mu = 7, \sigma = 4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 7}{4}

Z = 0.25

(a) Why is Kenji considered a better runner than Nedda, even though Nedda ran faster than he?

Kenji's time had a lower z-score, which means that he is better compared to other runners on his level, and better to his peers compared to Nedda.

(b) Who is the fastest runner with respect to his or her class? Explain why

Rachel, because her time had the lowest z-score.

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