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Nadya [2.5K]
3 years ago
11

An electric pole is 10m high if it's shadow is 10×√3 in length find the elevation ofthe sum

Mathematics
1 answer:
lianna [129]3 years ago
6 0
First, Look at the attached picture as a reference.

Now, using Pythagoras theorem, 

AC^2=AB^2+BC^2 \\\\AC=\sqrt{AB^2+BC^2 }\\\\AC=\sqrt{10^2+(10\sqrt3)^2}\\\\ AC = \sqrt{100+300}\\\\AC=\sqrt{400}\\\\AC=20~in.

Now, lets find the elevation of the sun.

<span> </span>tan\theta =  \frac{AB}{BC} \\\\ tan\theta =  \frac{10}{10\sqrt3} \\\\ \theta = tan^{-1} \left(\frac{10}{10\sqrt3}\right) \\\\ \boxed{\theta = 30  \°}

∴ The elevation of the sun is 30°

 

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3 years ago
Mr.diaz’s class is taking a field trip to the science museum there are 23 students in the class and a student admission ticket i
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4 years ago
What is the perimeter of a sandbox with the coordinates of (12,14),(12,17),and (16,14)
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3 years ago
Assume that we have m coins. We toss each one of them n times. The probability of heads showing up for each coin isp. What’s the
olga nikolaevna [1]

Answer:

1-(1-p^n)^m

Step-by-step explanation:

For a coin, the probability of head showing in a single toss is p.

P(H)=p

Its complement, the probability of not head is

P(\Sim H)=1-p

This is a binomial distribution. In n tosses, the probability of having all heads (i.e. n heads) is

P(\text{all heads})=\binom{n}{n}p^n(1-p)^0=p^n

Let's call this value a.

For m coins, we determine the probability of at least 1 coin showing all heads by first finding its complement i.e. the probability of no coin showing all heads. This is also a binomial distribution.

P(\text{no coin showing all heads})=\binom{m}{0}a^0(1-a)^m=(1-a)^m

P(\text{at least 1 coin showing all heads})=1-P(\text{no coin showing all heads})

P(\text{no coin showing all heads})=1-(1-a)^m=1-(1-p^n)^m

8 0
3 years ago
How do you solve 13-2n=19
tangare [24]
See step by step:

<span> 13-2n=19
</span>- 2n = 19 - 13
- 2n = 6
n = -6/2
n = -3

8 0
3 years ago
Read 2 more answers
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