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sveticcg [70]
3 years ago
10

Write an equation of the line that passes through the points (-1, -2) and (2.4)

Mathematics
1 answer:
Lelu [443]3 years ago
3 0

Answer:

As eq of line passing through 2 points is

y-y1 = (y2-y1)/(x2-x1) ][ x -x1)

where (X1,y1)( x2, y2) denotes points lying on line

substitute (X1 ,y1) by( -1,-2) and (X2,y2) by( 2,4)

y+2 = 6/3 )( x+1)

y+2= 2x +2

y = 2x is required equation

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Compare and Contrast Graph y = 2x + 5 and y=-13x+5. Describe how these lines are alike and how they are different. *​
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Here are a couple I found:

<u>Similarities</u>:

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  • They are both in slope-intercept form.

<u>Differences</u>:

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<u></u>

<u>Explanation</u>:

Slope-intercept form is y = mx + b, and by looking at the equations, they both already fit that format, with m as their slope and b as their y-intercept. Also, since they both have a 5 as that "b," their y-intercepts are the same: (0,5).

As for differences, we can see that the coefficient in place of that "m" is positive in y = <u>2x</u> + 5 and negative in y = <u>-13x</u> + 5. Therefore, one line would rise due to their slope being positive and one would fall due to their slope being negative. They also have two different x-intercepts, which we can calculate by substituting 0 in place of the y, then isolating x.

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