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Mazyrski [523]
3 years ago
12

A student working on a report about mathematicians decides to find the 98% confidence interval for the difference in mean age at

the time of math discovery for Greek mathematicians versus Egyptian mathematicians. The student finds the ages at the time of math discovery for members of both groups, which include all Greek and Egyptian mathematicians, and uses a calculator to determine the 98% confidence interval based on the t distribution. Why is this procedure not appropriate in this context? (4 points)
Mathematics
1 answer:
balandron [24]3 years ago
6 0

Answer:

The entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used.

Step-by-step explanation:

A student working on a report about mathematicians decides to find the 98% confidence interval for the difference in mean age at the time of math discovery for Greek mathematicians versus Egyptian mathematicians. The student finds the ages at the time of math discovery for members of both groups, which include all Greek and Egyptian mathematicians, and uses a calculator to determine the 98% confidence interval based on the t distribution, <u>the entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used.</u> There is no as such explanation of this scenario, its just the answer mentioned above.

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4.3 Mr Mokwebo 's two sons, Refentse and Tokelo have just passed grade 7 and grade 9 respectively. He will give them some money
Bumek [7]

The amount of money each of Mr Mokwebo 's two sons; Tokelo and Refentse will get is R116 and R95 respectively.

<h3>How to write and solve equation:</h3>

  • Amount needed to buy chocolate = R253
  • Tokelo's money = x
  • Refentse's money = x - 21

Total amount needed = Tokelo's money + Refentse's money

253 = x + (x - 21)

253 = x + x - 21

253 = 2x - 21

253 - 21 = 2x

232 = 2x

divide both sides by 2

x = 232/2

x = 116

Therefore,

Tokelo's money = x = R116

Refentse's money = x - 21

= 116 - 21

= R95

Learn more about equation:

brainly.com/question/2972832

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6 0
2 years ago
What is the value of x in the equation log5 x = 4 jmap?
steposvetlana [31]
To solve for x we proceed as follows:
from the laws of logarithm, given that:
log_a b=c
then
a^c=b
applying the rationale to our question we shall have:
log_5 x=4
hence
5^4=x
x=625
Answer: x=625
5 0
3 years ago
Nadia will be x years old y years from now. How old was she z years ago?
Vsevolod [243]
A years old. Na but are you needing an equation ?
8 0
3 years ago
Does the point (9.5, 144) make sense in this context? Explain
Stolb23 [73]
No, (9.5, 144) does not make sense because there is no point of 9.5 and when you divide the ounces of water by the flavoring packets you end up with 12, and if you were to simplify that it would end up with 1 flavor packet and 12 ounces of water.
6 0
3 years ago
Read 2 more answers
Seven blue and four red balls are to be arranged in order. How many ways can this be done if (1) The blue balls are distinguisha
Sav [38]

Answer:

1) n = 39916800

2) n = 1663200

3) n = 330

Step-by-step explanation:

1) If the blue balls are distinguishable as are the red balls

Then you can arrange these balls in the following ways, we must use a permutation

In totally we have 11 balls, then

n = 11P11

n = \frac{11!}{(11-11)!} = 11! = 39916800\\  

2) If Blue balls are distinguishable, but the red balls are identical

In this case, we need to do a correction due to the red balls are identical and we cannot identify the difference when we interchange two red balls

n = \frac{11!}{4!}  = \frac{39916800}{24} = 1663200

3) If the balls of each color are indistinguishable

We proceed equal to the before case but we include a correction due to blue balls also

n = \frac{11!}{4!*7!} = \frac{39916800}{24*5040} = 330

7 0
3 years ago
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