The amount of money each of Mr Mokwebo 's two sons; Tokelo and Refentse will get is R116 and R95 respectively.
<h3>How to write and solve equation:</h3>
- Amount needed to buy chocolate = R253
- Tokelo's money = x
- Refentse's money = x - 21
Total amount needed = Tokelo's money + Refentse's money
253 = x + (x - 21)
253 = x + x - 21
253 = 2x - 21
253 - 21 = 2x
232 = 2x
divide both sides by 2
x = 232/2
x = 116
Therefore,
Tokelo's money = x = R116
Refentse's money = x - 21
= 116 - 21
= R95
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To solve for x we proceed as follows:
from the laws of logarithm, given that:
log_a b=c
then
a^c=b
applying the rationale to our question we shall have:
log_5 x=4
hence
5^4=x
x=625
Answer: x=625
A years old. Na but are you needing an equation ?
No, (9.5, 144) does not make sense because there is no point of 9.5 and when you divide the ounces of water by the flavoring packets you end up with 12, and if you were to simplify that it would end up with 1 flavor packet and 12 ounces of water.
Answer:
1) n = 39916800
2) n = 1663200
3) n = 330
Step-by-step explanation:
1) If the blue balls are distinguishable as are the red balls
Then you can arrange these balls in the following ways, we must use a permutation
In totally we have 11 balls, then
n = 11P11
2) If Blue balls are distinguishable, but the red balls are identical
In this case, we need to do a correction due to the red balls are identical and we cannot identify the difference when we interchange two red balls
3) If the balls of each color are indistinguishable
We proceed equal to the before case but we include a correction due to blue balls also
