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love history [14]
3 years ago
11

Write eight and fifteen hundredths in decimal notation

Mathematics
2 answers:
Alina [70]3 years ago
6 0

Answer:

8.15

Step-by-step explanation:

FrozenT [24]3 years ago
5 0

Answer:

0.08, 0.15

Step-by-step explanation:

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Which ordered pair is not a solution of the equation 3x+2y=-10? A: (-4,1) B: (-5,4) C:(2,-8)
Angelina_Jolie [31]
Plug in the values and see which ones do not fi:-

. A      3(-4) + 2(1) =  -10

that fits  so it must be B, C or D.
4 0
3 years ago
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DanielleElmas [232]

Answer:

Add the area of the rectangle with the semicircle.

10x4 + 0.5(3.14)(25)

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79.25

So the answer is C. 79.

Let me know if this helps!

4 0
3 years ago
"What is the probability of drawing a jack or queen from a standard deck of cards?"
Natasha2012 [34]
Well, there are 52 cards in a deck, with 4 suits. there is a Jack and queen per suit, so that is a total of 8 jacks and queens in the deck. that probability looks like 8:52 as a ratio, or 2:13 simplified. so, you are likely to draw a Jack or queen 8 out of 52 times, or 2 out of 13 times
5 0
3 years ago
How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
3 years ago
HELP!! WILL GIVE BRAINLIEST! EASY!!
MAVERICK [17]

Answer:

Option 2

Step-by-step explanation:

Mid point theorem:

The line segment joining the mid point of two sides of a triangle, is parallel to the third sides and this line segment is half the length of the third side

7 0
3 years ago
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