1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Georgia [21]
3 years ago
15

Factor by grouping 4c^3+8c^2-9c-18

Mathematics
1 answer:
Zolol [24]3 years ago
7 0

Answer:

4c^3+8c^2-9c-18

Step-by-step explanation:

You might be interested in
Which of the following is a Riemann Sum used to estimate?
fgiga [73]

Answer:

A. Area under a curve

Step-by-step explanation:

Edge 2021

5 0
3 years ago
Rewrite the expression with the given base. 25^3x with a base of 5.
svp [43]
Use\ (a^n)^m=a^{nm}\\\\25^{3x}=(5^2)^{3x}=5^{2\cdot3x}=5^{6x}
6 0
3 years ago
Write -12 7/8 as a decimal. (NEED ASAP WITH WORK)
seropon [69]
7/8 can be converted to .875 because 1/8 is .125 and .125*7=.875. Add -12 to it so the answer is -12.875
5 0
3 years ago
83 tens × 2 tens =166
FinnZ [79.3K]
1 cube= 1 unit
1 Rod (Long)= 10 units
10 Rods (Longs)= 1 flat (1 flat=100 units)
10 flat =1 cube(1 cube=1000 units)
83×10= 830
2×10=20
830×20= 16,600
Just wanted to add more to help you understand why 83 is multiplied by ten and 2 is multiplied by 10. Its because when we use Base ten blocks, tens represent 1 Rod (Long)= 10 units. Hope it helps more.

5 0
3 years ago
Read 2 more answers
For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to
erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

8 0
3 years ago
Other questions:
  • Which is a prime number? A. 39 B. 49 C. 81 D. 89
    11·2 answers
  • What's the slope of y= -x + 4​
    14·1 answer
  • HELP I DONT UNDER STAND INTERGERS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    5·2 answers
  • to download movies off the internet, you must pay 1.99 per movie,plus one time fee of 5.50 write an expression to show the total
    8·2 answers
  • I WILL GIVE BRAINLIEST
    15·1 answer
  • the 6:00 a.m. temperatures for four consecutive days in the town of Lincoln were -12.1 C, -7.8 C, -14.3 C and -7.2 C what was th
    13·1 answer
  • Help me out here pleaseeeeeeeeeee
    5·2 answers
  • Cancel oh we're on a shelf 1/3 of the cans fell off the show how many did not fall?​
    8·1 answer
  • What is the answer? I need help on this and it’s not popping up on here
    8·1 answer
  • Use slopes and y-intercepts to determine if the lines 5x-5y=-2 and -x+2y=4
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!