Which is greater 6,200 ft or 1 mi 900 ft?
2 answers:
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The equation (x + 2)² + (y - 1)² = 25 represents a circle that contain the point (-5 , -3) and has a center at (-2 , 1)
Step-by-step explanation:
The equation of a circle of center (h , k) and radius r is:
(x - h)² + (y - k)² = r²
The given is:
- The center of the circle is (-2 , 1)
- The circle passes through point (-5 , -3)
The length of the radius is the distance from the center of the circle
to a point on the circle
∵ The formula of the distance is
∵ The center of the circle is (-2 , 1)
∵ The circle passes through point (-5 , -3)
∴
∴
∴
∴
∴ r = 5
∵ The equation of the circle is (x - h)² + (y - k)² = r²
∵ The center of the circle is (-2 , 1)
∴ h = -2 and k = 1
∵ r = 5
∴ r² = (5)² = 25
- Substitute the values of h , k , r² in the equation of the circle
∴ (x - -2)² + (y - 1)² = 25
∴ (x + 2)² + (y - 1)² = 25
The equation (x + 2)² + (y - 1)² = 25 represents a circle that contains
the point (-5 , -3) and has a center at (-2 , 1)
Learn more:
You can learn more about the equation of the circle in brainly.com/question/9510228
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The co ordinates of P' is (-7,-2) and Q' is (-16, -8)
<u><em>Explanation</em></u>
PQ is rotated 180 degrees clockwise about P. It means <u>P and P' are the same points</u>.
According to the graph, the coordinates of P is (-7, -2) and Q is (2, 4)
When PQ is rotated 180 degrees clockwise about P, then <u>P or P' will be the mid-point of Q and Q' </u>
Suppose, the co ordinate of Q' is (x, y)
Now according to the mid-point formula, the coordinate of P or P' will be: , which is actually at (-7, -2)
Thus.....
So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)