25 POINTS PLEASE HELP !!

Mathematics

1 answer:

jekas [21]3 years ago

7 0

The last graph provided is the correct one. With points (-1,-3) (-3,0) (-3,-3)

You might be interested in

Solve for x: 2 over 3 (x − 4) = 2x. 2 −2 −8 −4

KIM [24]

Distribute 2/3 to the parentheses on the left side, combine like terms. 1 1/3 x= -2 2/3. Final answer is -2

4 0

3 years ago

Read 2 more answers

What are the coordinates of the vertex for f(x) = x2 + 4x + 10?

Nady [450]

F(x) = x² + 4x + 10

f(x) - 10 = x² + 4x

perfect square:
x² + 4x + 4 ⇒ (x + 2)²

(x + 2)² = x(x+2) + 2(x+2) = x² + 2x + 2x + 4 = x² + 4x + 4

f(x) - 10 + 4 = x² + 4x + 4
f(x) - 6 = (x+2)²
f(x) = (x+2)² + 6

3 0

3 years ago

PLEASE HELP!!

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

8 0

3 years ago

Add the two expressions.<br><br> 3z−4 and 2z + 5<br><br> Enter your answer in the box.

frosja888 [35]

Your answer is 5z+1 (wink) ;D

3 0

3 years ago

Read 2 more answers

General house cleaning (sweeping the floors, vacuuming, laundry etc.)

kobusy [5.1K]

Answer:

sleeping the floor and vacuuming

7 0

3 years ago