2 years ago

1. List the domain and range of the relation

Mathematics

1 answer:

Naddik [55]2 years ago

3 0

Answer:

Domain: {(7, 9, 0)}

Range: {(-2, 9, 11, 2)}

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V= 512^2/3* 19683^1/3*256^1/4

irina1246 [14]

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Step-by-step explanation:

V= $(512^{\frac{2}{3} } ) \times (19683^{\frac{1}{3} } )\times (256^{\frac{1}{4} } )\\$

$2^{9} = 512\\2^{8} = 256\\19683^{\frac{1}{3} } = 27\\$

putting values in equation

V= $2^{9(^{\frac{2}{3} } )} \times 27 \times 2^{8^({\frac{1}{4}) } } \\$ let it be equation 1

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putting values in equation 1

$V= 2^6\times 27\times 2^2$

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V= 6912

Keywords: Algebra

Learn more about algebra at:

#learnwithBrainly

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