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3 years ago

9

A pizza parlor offers a choice of 16 different toppings. how may three-topping pizzas are possible

1 answer:

Mariulka [41]3 years ago

7 0

48. 16 times 3 is 48:)

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How to turn 0.07 with the repeating bar on the 7 into a fraction?

trapecia [35]

Use a 9 instead of a ten. for example, 7/(9 x 10) = 7/90

5 0

3 years ago

Find the slope of the line that passes through (-24, 6) and (9, 87). Simplify your answer and write it as a proper fraction, imp

Novosadov [1.4K]

Answer: The equation of a straight line is:

y = mx + b

m is the slope, and that is -2.

Hope this helps:/

3 0

3 years ago

Read 2 more answers

Po The diameter of a circular fountain in a city park is 28 feet. A sidewalk that is 3.5 feet will be built around the fountain.

jarptica [38.1K]

Answer:

Area of sidewalk = $346.5 ft^2$

Bags of concrete = 277

Step-by-step explanation:

The diameter of the circular fountain is 28 ft. Radius = 28 / 2 = 14 ft

The thickness of the sidewalk is 3.5 ft. This means they want to add 3.5 ft to each radius of the fountain.

To find the area of the sidewalk alone, we have to find the area of the sidewalk alone and then subtract it from the area of the sidewalk and fountain.

That is:

$A_s = A_{s+f} - A_f$

The fountain is circular and its radius is 14 ft. Hence, its area will be:

$A_f = \pi r^2$

$A_f = \pi *14^2 = 616 ft^2$

The sidewalk and fountain together also form a circular shape. Their joint radius will be:

R = 14 + 3.5 = 17.5 ft

Hence, the area will be:

$A_{s + f} = \pi R^2 \\A_{s + f} = \pi * 17.5 * 17.5 = 962.5 ft^2$

Hence, the area of the sidewalk alone will be:

$A_s = 962.5 - 616 = 346.5 ft^2$

This is the area of the sidewalk.

For every square foot ( $ft^2$ ), 0.8 bag of concrete will be used. This means that for $346.5 ft^2$ :

Bags of concrete = 0.8 * 346.5 = 277.2 ≅ 277

At least 277 bags of concrete will be used for the new sidewalk.

5 0

4 years ago

Peter makes 15 dollars an hour and he spends 25 dollars a day on transportation and food. Write an expression to describe his sp

Nata [24]

Answer:

15h - 25

Step-by-step explanation:

4 0

3 years ago

Find the slope-intercept form of the equation of the line that passes through the point (5,1) and is perpendicular to the line 2

Vlad1618 [11]

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

Convert 2x + 5y = 10 to the slope0intercept form:

$2x+5y=10$ <em>subtract 2x from both sides</em>

$5y=-2x+10$ <em>divide both sides by 5</em>

$y=-\dfrac{2}{5}x+2$

Let $k:y=m_1x+b_1$ and $l:y=m_2x+b_2$

$l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}$

We have $m_1=-\dfrac{2}{5}$

Therefore

$m_2=-\dfrac{-\frac{2}{5}}=\dfac{5}{2}$

We have the equation of a line:

$y=\dfrac{5}{2}x+b$

Put the coordinates of the point (5, 1) to the equation of a line:

$1=\dfrac{5}{2}(5)+b$

$1=\dfrac{25}{2}+b$ <em>subtract $\dfrac{25}{2}$ from both sides</em>

$-\dfrac{23}{2}=b\to b=\dfrac{23}{2}$

Answer: $\boxed{y=\dfrac{5}{2}x+\dfrac{23}{2}}$

4 0

3 years ago