Take a look at the image below.
Answer:
C
Step-by-step explanation:
Under a reflection in the y- axis
a point (x, y ) → (- x, y ), thus
A(3, 4 ) → A'(- 3, 4 )
Since the point A and it's reflection lie on a horizontal line then
distance between = | 3 + 3 | = | 6 | = 6
9We have such eqation
Q

/*9 (multiply both sides by 9)
9Q+5=

/-5 both sides
9Q=

9Q=

9Q=

9Q=-

/:9 divide both sides by 9
Q=-

Q
![\frac{21}{6*9} =- \frac{21}{54}=[tex] \frac{7}{18}](https://tex.z-dn.net/?f=%20%5Cfrac%7B21%7D%7B6%2A9%7D%20%3D-%20%5Cfrac%7B21%7D%7B54%7D%3D%5Btex%5D%20%5Cfrac%7B7%7D%7B18%7D%20)
- its the answer
Pls. see attachment.
We need to solve for the angles of the smaller triangle in
order to solve for the angle of the larger triangle which would help us solve
the missing measurement of a side.
Given:
51 degrees.
Cut the triangle into two equal sides and it forms a right
triangle. All interior angles of a triangle sums up to 180 degrees.
180 – 51 – 90 = 39 degrees
39 degrees * 2 = 78 degrees.
Angle Q is 78 degrees.
In the bigger triangle, 4.3 is the hypotenuse. We need to
solve for the measurement of the long leg which is the opposite of the 78
degree angle.
We will use the formula:
Sine theta = opposite / hypotenuse
Sin(78 deg) = opposite / 4.3
Sin(78 deg) * 4.3 = opposite
4.21 = opposite. This is also the height of the triangle.
Area of a triangle = ½ * base * height
A = ½ * 3units * 4.21units
A = 6.315 square units.