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3 years ago

Whats the 11th term of 2,6,18,54

1 answer:

8 0

The 11th term would be 39,366.

The rule for this sequence is 3n (n times 3). Simplying multiplying by 3 until you get to the 11th term (54 * 3 * 3 * 3 * 3 * 3 * 3), would give you this answer.

I hope this helps!!

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HELP ME PLEASE!!!!!! ASAP!!!!!!!

Misha Larkins [42]

Answer:

your answer is C

Step-by-step explanation:

7 0

3 years ago

Jasmine created a scale drawing of her room. She used a scale of 1 in:3 feet. The drawing is 8 inches long by 6 inches wide. Wha

sergiy2304 [10]

Answer:

The area of the room is 432 square feet

Step-by-step explanation:

Let us use the ratio method to solve the question

∵ The scale drawing of the room is 1 inch: 3 feet

→ That means each 1 inch in the drawing represents 3 feet in real

∵ The drawing is 8 inches long by 6 inches wide

∴ The drawing length of the room = 8 inches

∴ The drawing width of the room = 6 inches

→ By using the ratio method

→ inches : feet

→ 1 : 3

→ 8 : L

→ 6 : W

→ By using the cross multiplication

∵ 1 × L = 8 × 3

∴ L = 24

∴ The actual length of the room is 24 feet

∵ 1 × W = 6 × 3

∴ W = 18

∴ The actual width of the room is 18 feet

Use the formula of the area of the rectangle to find the area of the room

∵ Area of rectangle = length × width

∴ Area of the room = 24 × 18

∴ Area of the room = 432 feet²

∴ The area of the room is 432 square feet

8 0

3 years ago

F(x) = 9x2 - 4<br><br> Find the zeros of the function

Delvig [45]

Answer:

I believe that the answer is 14.

Step-by-step explanation:

hope it helped

4 0

3 years ago

A triangle has an area of 56 square units. It's night is 14 units. What is the length of its base?

NNADVOKAT [17]

Answer:

8 units

Step-by-step explanation:

b(14)/2 = 56

14b = 112

b = 8 units

4 0

3 years ago

Q1: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.

marin [14]

Answer:

C. hyperbola; $9x^2-25y^2-250y-850=0$

Step-by-step explanation:

The given conic has equation:

$9x^2-25y^2=225$

Divide through by 225.

$\frac{9x^2}{225}-\frac{25y^2}{225}=\frac{225}{225}$

$\frac{x^2}{25}-\frac{y^2}{9}=1$

This is a hyperbola centered at the origin.

The hyperbola has been translated from the origin to (0,5).

The translated hyperbola will have equation;

$\frac{(x-0)^2}{25}-\frac{(y-5)^2}{9}=1$

Multiply through by 225.

$9(x-0)^2-25(y-5)^2=225$

Expand

$9x^2-25(y^2-10y+25)=225$

$9x^2-25y^2+250y-625=225$

Rewrite in general form;

$9x^2-25y^2+250y-625-225=0$

$9x^2-25y^2+250y-850=0$

3 0

3 years ago