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4 years ago

Whats the 11th term of 2,6,18,54

1 answer:

8 0

The 11th term would be 39,366.

The rule for this sequence is 3n (n times 3). Simplying multiplying by 3 until you get to the 11th term (54 * 3 * 3 * 3 * 3 * 3 * 3), would give you this answer.

I hope this helps!!

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Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times

Elina [12.6K]

Answer:

The probability is $P(A') = 0.485$

Step-by-step explanation:

Let assume that the number of computer produced by factory C is k = 1

So From the question we are told that

The number produced by factory A is 4k = 4

The number produced by factory B is 7k = 7

The probability of defective computers from A is $P(A) = 0.04$

The probability of defective computers from B is $P(B) = 0.02$

The probability of defective computers from C is $P(C) = 0.03$

Now the probability of factory A producing a defective computer out of the 4 computers produced is

$P(a) = 4 * P(A)$

substituting values

$P(a) = 4 * 0.04$

$P(a) = 0.16$

The probability of factory B producing a defective computer out of the 7 computers produced is

$P(b) = 7 * P(B)$

substituting values

$P(b) = 7 * 0.02$

$P(b) = 0.14$

The probability of factory C producing a defective computer out of the 1 computer produced is

$P(c) = 1 * P(C)$

substituting values

$P(c) = 1 * 0.03$

$P(b) = 0.03$

So the probability that the a computer produced from the three factory will be defective is

$P(t) = P(a) + P(b) + P(c)$

substituting values

$P(t) = 0.16 + 0.14 + 0.03$

$P(t) = 0.33$

Now the probability that the defective computer is produced from factory A is

$P(A') = \frac{P(a)}{P(t)}$

$P(A') = \frac{ 0.16}{0.33}$

$P(A') = 0.485$

3 0

3 years ago

gallons of water can fill a pool that is 50 yards by 20 yards and is 9 feet deep? (Assume 7 1/2 gallons per cubic foot.)

saul85 [17]

L = 50 yards or 150 feet W = 20 yards or 60 feet H = 9 feet V = 150 * 60 * 9 V = 81000 cubic feet then multiply the volume, 81000, by 7.5, or 607,500 gallons.
hope i helped

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%7D%20%3D2x%2B2" id="TexFormula1" title="\sqrt[3]{x+1} =2x+2" alt="\sqrt

Lina20 [59]

The answer is down below