This question is incomplete and it also lacks an attached diagram.
Find attached to this answer the appropriate diagram.
Complete Question:
The conditional relative frequency table was generated using data that compared the cost of one ticket for a performance and the method by which the ticket was purchased.
Given that Lorenzo paid more than $30 for a ticket, what is the probability that he purchased the ticket at the box office? Express the answer in decimal form
Answer:
0.14
Step-by-step explanation:
From the attached diagram, we were given a table that contained known values:
The number of tickets that were purchased online we have 2 categories
a) Not more than $30 = 0.7
b) More than $30 = 0.86
The number of tickets that were purchased at the box office also had 2 categories.
a) Not more than $30 = 0.3
b) More than $30 = 0.14
The probability that the ticket Lorenzo paid more than $30 for was purchased at the box office
= P( more than $30 at the box office)
= 0.14
Answer:
on p or q put
Step-by-step explanation:
1) p and q true
2) q false
3) p false
4) p and q false
I believe the answer you want is the third option
Step-by-step explanation:
angle YWX = angle YXW ...eqn 1
angle XYZ = angle WYX (0.5) = 15x...eqn 2
angle YXZ = angle YXW = 2x + 5...eqn 3
=> from eqn 1 and 3 we get...
angle YWX = 2x + 5 ...eqn 4
=> from eqn 2 we get
angle WYX = 2 × angle XYZ = 30x...eqn 5
a triangle has a total of 180deg,
=>angle WYX + angle YWX + angle YXW = 180deg
=> 30x + 2x +5 + 2x +5 = 180deg
=> 34x +10 =180deg
=> x = 5deg
subst x = 5deg in eqn 5, we get
angle WYX = 30 × 5 = 150deg
.75 because .75 is .25 from 1.0 and .25 from .5