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SashulF [63]
3 years ago
6

4x + 3y=-8 -8x + y=-12

Mathematics
2 answers:
Tju [1.3M]3 years ago
6 0
Actually the correct answer is x:1 and y:-4 you can check this by substitute the x and y into the equayion
emmasim [6.3K]3 years ago
5 0
X is 1 while Y is 4/3
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HELP PLZ SORRY LAST ONE WAS BLURRY
Andru [333]
0.25 ....decimal

3/4, 3:4....ratio

2/3 = 6/9....equivalent fractions, fractions

4/8 --> 1/2....equivalent fractions,fraction,simplest form


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4 years ago
Please help me asap​
icang [17]
A, B, B,C for 8,9,10,11
7 0
3 years ago
Read 2 more answers
Whats wrong in this equation ?
Inga [223]
The second step is wrong. What should've been done is to find greatest common factor (gcf) of 1/6 and -2. This is because you cannont add together a number with a variable to a number without a variable. So get the variable by itself by subtracting 1/6 from both sides.

1/5x + 1/6 = -2
___— 1/6_— 1/6
____________


Turn -2 into a fraction and find the gcf of -2 and 6:

1/5x + 1/6 = -2
___— 1/6_— 1/6
____________

1/5x = -2/1 — 1/6 ——> 1/5x = -12/6 — 1/6
1/5x = -13/6

Then divide each side by 1/5 to get the variable by itself; remeber: when dividing a fraction by a fraction, you multiply by the reciprocal.

5/1 • 1/5x = -13/6 • 5/1
x = 65/6

Then, simplify

65/6} 10.83 or 10 83/100
6 0
3 years ago
Solve the inequality.    <br>       3m ≤ –9<br> A.m ≥ –3<br> B.m ≤ –3 <br> C.m ≥ 6  <br> D.m ≤ –6
marin [14]
3m \leq -9\ /:3 \ \ \ \Rightarrow\ \ \ m \leq -3\ \ \ \Rightarrow\ \ \ Ans.\ B
6 0
3 years ago
In George’s neighborhood there are 33 cats and 33 dogs roaming free.What percent of the animals roaming free are dogs?
Alexxx [7]
First, we'll figure out how many animals there are in total by adding up the cats and the dogs. In this case, we have 33+33=66 total animals. Then we need to figure out what fraction of these 66 animals are dogs:
\frac{33}{60}=\frac{1}{2}

So half of the animals are dogs. To write that as a percent, we need the fraction to be over 100, so:
\frac{1}{2}=\frac{50}{100}

50% of the animals are dogs.
6 0
3 years ago
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