Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr

8 0

3 years ago

Please see the question and solve plz

Korolek [52]

Answer:

Step-by-step explanation:

sin²β + sin²β×tan²β = tan²β

sin²β( 1 + tan²β ) = tan²β

~~~~~~~~~~~~~~~~

sin²β + cos²β = 1

$\frac{sin^2\beta }{cos^2\beta }$ + $\frac{cos^2\beta }{cos^2\beta }$ = $\frac{1}{cos^2\beta }$ ⇒ tan²β + 1 = sec²β ⇔ 1 + tan²β = sec²β

~~~~~~~~~~~~~~

1 + tan²β = $\frac{1}{cos^2 \beta }$

L.H. = sin²β ( $\frac{1}{cos^2 \beta }$ ) = tan²β

R.H. = tan²β

7 0

3 years ago

Write an expression to represent: The sum of ten and the quotient of a number and 6.

hoa [83]

Answer:

10 + x/6

Step-by-step explanation:

8 0

3 years ago

A) 4

Shkiper50 [21]

Answer:

i think c

Step-by-step explanation:

8 0

3 years ago