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3 years ago

Which of the following is a correct cosine ratio for the figure?

Mathematics

1 answer:

LenKa [72]3 years ago

4 0

B! cosine is adjacent over hypotenuse

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Please help me I need your help I please you to death please please please please I’m begging you for your help to death right n

vampirchik [111]

Answer:

Step-by-step explanation:

Don't really want you to die ^^

d = total earnings so it's the dependent/y variable

h = hours so it's the independent/x variable

9.25 = earnings per hour or slope

b = 0 since Chakan starts off with $0

Using y = mx + b...

d = 9.25h + 0 or d = 9.25h

3 0

3 years ago

Which of the following best describe(s) the slope of a linear function?

sleet_krkn [62]

Intersecting with the y-axis is the correct answer

5 0

3 years ago

Integers is

adell [148]

Answer:

See below

Step-by-s.ep explanation:

6. Let the 3 integers be k-2, k and k+2.

So k(k+2)-k(k-2) = 28

k^2 + 2k - k^2 + 2k = 28

4k = 28

k = 7.

So the 3 integers are 5, 7 and 9.

7 0

3 years ago

(n2+11n+25) ÷ ( n+5) long division

zmey [24]

Answer:

$(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,R5$

Step-by-step explanation:

Synthetic division:

-5 | 1 11 25

____-5 -30

1 6 | -5

Therefore, $(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,_$R$5$

Long division:

n+5 | n² + 11n + 25

- n² + 5n____ <-- n

6n + 25

- 6n + 30 <-- 6

-5 | n+6

Therefore, $(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,_$R$5$

6 0

3 years ago

A physical education teacher plans to divide the seventh graders at Wilson Middle School into teams of equal size of year-ending

Crank

Step-by-step explanation:

Consider the provided information.

The total number of students are: 24+26+21=71

He wants each team will have the same number of students between 5 and 9.

The number between 5 to 9 are 6, 7 and 8.

The number 71 is a prime number so we need to divide the 71 students in group so that minimum students left without team.

Dividing 6 students in each group.

Number of teams: $\frac{71}{6}$ = 11 teams and 5 students.

Dividing 7 students in each group.

Number of teams: $\frac{71}{7}$ = 10 teams and 1 students.

Dividing 8 students in each group.

Number of teams: $\frac{71}{8}$ = 8 teams and 7 students.

Thus, we can not divide 71 students into equal teams, but 70 divided by 7 gives the least students left out i.e 10 teams each with 7 students and only 1 student will remain at last.

6 0

3 years ago