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3 years ago

Point A is located at -5/8 and point B is located at -2/8. What is the distance between points A and B

1 answer:

3 0

I think those are coordinates of points, (-5,8) and (-2,8)
so you just need to use distance formula ((8-8)^2+(-2+5)^2)=0+9=9
square root 9=3

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PLEASE HELPPPPPP ASAPPP<br>I WILL GIVE BRAINLEST FOR THE CORRECT ANSWER

guajiro [1.7K]

Answer:

a. Find the multiples of 4 and 12 in the 30 to 40 range:

4 ⇒ 32, 36, 40

12 ⇒ 36

Answer = 36

b. Divisors of 24 ⇒ 2, 3, 4, 6, 8, 12, 24

Answer = 3

3 is the only odd divisor.

c. Gcd = Greatest common divisor that isn't zero.

35 divisors ⇒ 1, 5, 7, 35

42 divisors ⇒ 1, 2, 3, 6, 7, 14, 21, 42

Answer = 7

d. 98 divisors ⇒ 1,2,7,14,49,98

99 divisors ⇒ 1,3,9,11,33,99

Answer = 1

e. Answer = 25.

A number's greatest divisor is its own self.

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Molodets [167]

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Step-by-step explanation:

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2 years ago

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In a circle with a radius of 5cm and is centered at point O, angle AOB intercepts arc AB. Arc AB has a length of 10cm. What is t

Elenna [48]

<span>circumference of circle = 2*pi*r given r = 5 so circumference = 31.42 now we know 360 degree is uniformly distributed on this circumference so x/360=10/31.42 so x= 114.65 so option C.) 114.65 is the answer</span>

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2 years ago

Complete the point-slope equation of the line through (2,3 and (7,4). Use exact numbers.

uysha [10]

The point-slope equation of the line is $y-3=\frac{1}{5}(x-2)$

Step-by-step explanation:

The form of the point-slope equation is $y-y_{1}=m(x-x_{1})$ , where

m is the lope of the line
$(x_{1},y_{1})$ is a point lies on the line

The slope of a line $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ , where

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ are two points on the line

∵ The line through (2 , 3) and (7 , 4)

∴ $x_{1}$ = 2 and $x_{2}$ = 7

∴ $y_{1}$ = 3 and $y_{2}$ = 4

- Substitute these value in the rule of the slope

∵ $m=\frac{4-3}{7-2}=\frac{1}{5}$

∴ the slope of the line is $m=\frac{1}{5}$

Let us substitute the value of the slope and the coordinates of point $(x_{1},y_{1})$ in the form of the equation

∵ $y-y_{1}=m(x-x_{1})$

∵ $x_{1}$ = 2 and $y_{1}$ = 3

∵ $m=\frac{1}{5}$

∴ $y-3=\frac{1}{5}(x-2)$

The point-slope equation of the line is $y-3=\frac{1}{5}(x-2)$

Learn more:

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