-7 + 56x = 105
56x = 105 + 7
56x = 112
x = 2
Answer:
- 0.100
Step-by-step explanation:
Length of the ladder, H = 6 m
Distance at the bottom from the wall, B = 1.3 m
Let the distance of top of the ladder from the bottom at the wall is P
Thus,
from Pythagoras theorem,
B² + P² = H² .
or
B² + P² = 6² ..............(1) [Since length of the ladder remains constant]
at B = 1.3 m
1.3² + P² = 6²
or
P² = 36 - 1.69
or
P² = 34.31
or
P = 5.857
Now,
differentiating (1)

at t = 2 seconds
change in B = 0.3 × 2= 0.6 ft
Thus,
at 2 seconds
B = 1.3 + 0.6 = 1.9 m
therefore,
1.9² + P² = 6²
or
P = 5.69 m
on substituting the given values,
2(1.9)(0.3) + 2(5.69) ×
= 0
or
1.14 + 11.38 ×
= 0
or
11.38 ×
= - 1.14
or
= - 0.100
here, negative sign means that the velocity is in downward direction as upward is positive
78 x 100 = 7800
<span>How many times does 190 go into 780? </span>
<span>≈ 4....190 x 4 = 760 </span>
<span>780 - 760 = 20...bring down the extra 0 to make it 200. </span>
<span>How many times does 190 go into 200? </span>
<span>≈ 1...subtract 190 from 200 to get a remainder of 10 </span>
<span>190 ÷ 7800 ≈ 41</span>
Hope I Helped You!!! :-)
Have A Good Day!!!