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2 years ago

Help ASAP please....

Mathematics

2 answers:

Kisachek [45]2 years ago

4 0

The correct answer would be D. 110

UkoKoshka [18]2 years ago

4 0

Answer:

Step-by-step explanation:

we know that UPR is a straight line so QPR and QPU equals 180 degrees

since we have QPR already we just have to do 180 - 70 = 110

so 110 is our answer

hope this helps <3

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Which of the following statements is true?

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The number -4 is a whole number

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2 years ago

When 24 is subtracted from a number and that difference is multiplied by 1/4, the result is 4.

Katen [24]

If (x-24)0.25 = 4, distribute 0.25 within the parenthesis.
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2 years ago

HELP ME WITH THIS EQUATION! 11 = y – 6 *

Blizzard [7]

Answer:

Step-by-step explanation:

here you go mate'

step 1

11 = y-6 equation

step 2

11+6=y-6+6 add 6 to the sides

answer

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2 years ago

Read 2 more answers

find the missing side. round to the nearest tenth. use pythagorean theorem to find the third side length

emmasim [6.3K]

Answer:

x is tangent of 39 = x/ 19, tangent of 39 is 3. 615...... then 19 multiply by 3.615....., x would get 68. 68

Step-by-step explanation:

tangent is opposite over adjacent then put all your numbers in to the formula.

4 0

2 years ago

Unit 3 homework 6 Gina Wilson

Sonja [21]

Answer:

5) The equation of the straight line is 2 x - y + 1 =0

6) The equation of the straight line is x + y -5 =0

7) The equation of the straight line is 5 x + 6 y - 24 =0

8) The equation of the straight line is x - 4 y -4 =0

9) The equation of the parallel line is 3x + y -19 =0

Step-by-step explanation:

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (1,3) , ( -3,-5)

$m = \frac{-5-3 }{-3-1 } = \frac{-8}{-4} = 2$

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

$y - 3 = 2 ( x - 1 )$

y = 2x - 2 +3

2 x - y + 1 =0

The equation of the straight line is 2 x - y + 1 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (1,4) , ( 6,-1)

$m = \frac{-1-(4) }{6-1 } = \frac{-5}{5} = -1$

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

$y - 1 = -1 ( x - 4 )$

y - 1 = - x +4

The equation of the straight line is x + y -5 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (-12 , 14) , ( 6,-1)

$m = \frac{-1-(14) }{6+12 } = \frac{-15}{18} = \frac{-5}{6}$

$y - 14 = \frac{-5}{6} ( x - (-12) )$

6( y - 14 ) = - 5 ( x +12 )

6 y - 84 = - 5x -60

5 x + 6 y -84 + 60 =0

5 x + 6 y - 24 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (-4 , -2) , ( 4 , 0)

$m = \frac{0+2}{4 +4} = \frac{2}{8} = \frac{1}{4}$

$y - (-2) =\frac{1}{4} ( x - (-4) )$

4 ( y + 2) = x + 4

x - 4 y -4 =0

The equation of the line y = 3x + 6 is parallel to the line

3x + y + k =0 is passes through the point ( 4,7 )

⇒ 3x + y + k =0

⇒ 12 + 7 + k =0

⇒ k = -19

The equation of the parallel line is 3x + y -19 =0

4 0

2 years ago