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Elenna [48]
3 years ago
8

F(x)=2x^2-x-10 part a: what are the X intercepts of the graph of f(x)? Show your work

Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0
A. x intercepts are where the graph hits the x axis or where f(x)=0
0=2x^2-x-10
solve
hmm
we can use the ac method
multiply 2 and -10 to get -20
what 2 numbers muliply to get -20 and add to get -1 (the coefint of the x term)
-5 and 4
split the midd into that
0=2x^2+4x-5x-10
group
0=(2x^2+4x)+(-5x-10)
factor
0=2x(x+2)-5(x+2)
undistribute
0=(x+2)(2x-5)
set each to 0
0=x+2
0=-2

0=2x-5
5=2x
5/2=x

x intercepts are at x=-2 and 5/2 or the points (-2,0) and (5/2,0)


B. ok, so for f(x)=ax^2+bx+c
if a>0, then the parabola opens up and the vertex is a minimum
if a<0 then the parabola opens down and the vertex is a max

f(x)=2x^2-x-10
2>0
opoens up
vertex is minimum

ok, the vertex

the x value of  the vertex in f(x)=ax^2+bx+c= is -b/(2a)
the y value of the vertex is f(-b/(2a)) so
given
f(x)=2x^2-x-10
a=2
b=-1
-b/2a=-(-1)/(2*2)=1/4
f(1/4)=2(1/4)^2-(1/4)-10
f(1/4)=2(1/16)-1/4-10
f(1/4)=1/8-1/4-10
f(1/4)=1/8-2/8-80/8
f(1/4)=-81/8
so the vertex is (1/4,-81/8) or (0.25,-10.125)


C. graph the x intercepts and the vertex
the vertex is min and the graph goes through the x intercepts
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Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let m and w be the subscript for men and women players. The population proportions would be pm and pw

Pm - Pw = difference in the proportion of male and female players.

The null hypothesis is

H0 : pm = pw

pm - pw = 0

The alternative hypothesis is

Ha : pm ≠ pw

pm - pw ≠ 0

it is a two-tailed test

Sample proportion = x/n

Where

x represents number of success

n represents number of samples

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xm = 1027

nm = 2441

Pm = 1027/2441 = 0.42

For women,

xw = 509

nw = 1273

Pw = 509/1273 = 0.4

The pooled proportion, pc is

pc = (xm + xw)/(nm + nw)

pc = (1027 + 509)/(2441 + 1273) = 0.41

1 - pc = 1 - 0.41 = 0.59

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Since it is a 2 tailed test, we would find the p value by doubling the area to the right of the z score to include the area to left.

Area to the right from the normal distribution table is

1 - 0.881 = 0.119

P value = 0.119 × 2 = 0.238

Since 0.05 < 0.238, we would accept the null hypothesis

Therefore, there is no sufficient evidence to conclude that that men and women have unequal success in challenging calls.

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