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Harrizon [31]
2 years ago
13

The L.C.M of 2and 4 is what?​

Mathematics
2 answers:
Anna35 [415]2 years ago
4 0
It is 4



Hope it helps you
KiRa [710]2 years ago
3 0

Hello.

First, let's clarify what the LCM stands for.

L stands for Least

C stands for Common

M stands for Multiple

So we need to find the Least Common Multiple of 2 and 4.

Let's list the first 5 multiples of 2:

2, 4, 6, 8, 10

Now, the first 5 multiples of 4:

4, 8, 12, 16, 20

As we can see, 4 is the LCM.

I hope it helps.

Have an outstanding day. :)

\boxed{imperturbability}

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The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

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The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

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Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
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