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3 years ago

Can someone pls help me find what is 1/10+12/20?

Mathematics

2 answers:

irga5000 [103]3 years ago

7 0

Answer:

$\frac{7}{10}$

Step-by-step explanation:

$\frac{1}{10}$ can also be written as $\frac{2}{20}$

$\frac{2}{20} +\frac{12}{20} =\frac{14}{20}$

Simply to $\frac{7}{10}$

-OTHER METHOD-

$\frac{12}{20}$ can be simplified to $\frac{6}{10}$

$\frac{1}{10} +\frac{6}{10} =\frac{7}{10}$

krek1111 [17]3 years ago

6 0

Answer:

7/10

Step-by-step explanation:

1/10=2/20

2/20 + 12/20 = 14/20

14/20=7/10

(Divide 14 by 2 to get 7, and divide 20 by 2 to get 10. Therefore you get 7/10).

Another way:

1/10+ 12/20

12/20 can be simplified to 6/10.

1/10 + 6/10 = 7/10

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3 years ago

Read 2 more answers

The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E

Gnoma [55]

Answer:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

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Step-by-step explanation:

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$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

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Required

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$\triangle CBA {\displaystyle \sim } \triangle FED$ $\triangle CBA {\displaystyle \sim } \triangle FDE$ $\triangle BAC {\displaystyle \sim } \triangle EFD$

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The given triangles, implies that:

$A {\displaystyle \sim } \ D$

$B {\displaystyle \sim } \ E$

$C {\displaystyle \sim } \ F$

By taking each sides of both triangle, one after the other; the possible similar triangles are:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

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