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prohojiy [21]
4 years ago
5

Help me plz only number 22

Mathematics
1 answer:
VikaD [51]4 years ago
3 0
Just multiply the fractions by 32
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The difference in our ages is 3 the sum of our ages is 25 how old are we
Doss [256]
You are 11 and 14

You can find this by guessing and checking, add any numbers that are 3 apart from each other.

14-11=3
14+11=25
5 0
3 years ago
One fourth of a number q is 3 more than three times a number w. Solve for q.
Butoxors [25]
1/4q = 3w + 3...multiply both sides by 4
q = 4(3w + 3)
q = 12w + 12 <===
5 0
3 years ago
Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua
goblinko [34]
<h2>Hello!</h2>

The answer is:  There is a total of 5.797 gallons pumped during the given period.

<h2>Why?</h2>

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

D(t)=\frac{5t}{1+3t}

So, the integral will be:

\int\limits^4_0 {\frac{5t}{1+3t}} \ dx

So, integrating we have:

\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx

Performing a change of variable, we have:

1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}

Then, substituting, we have:

\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du

\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )

\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du

\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]

Reverting the change of variable, we have:

\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]

Then, evaluating we have:

\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0
4 years ago
I need help with number 1​
Andreas93 [3]

Answer:

Step-by-step explanation:

Given

Points: (0,3) and (-4,-1)

Formula

x = 0 to find the y intercept

m = (y2 - y1)/(x2 - x1)

Solution

y2 = 3

y1 = - 1

x2 = 0

x1 = - 4

m = (3 - -1)/(0 - - 4)

m = 4/4

m = 1

You have y = mx + b so m = 1

the general equation becomes y = x + b

Use point (0,-4)

y = x + b

- 4 = 0 + b

b = - 4

y = x - 4

5 0
3 years ago
Read 2 more answers
The population of Salisa is 12,500 and increases by 300 each month. The population of Corsair is 13,200 and increases by 200 eac
ludmilkaskok [199]

It will take seven months for the population of each city to be the same.

On month seven, Salisa's population will be 14,600. (300x7=2,100+12,500=14600)

On month seven, Corsair's population will be 14,600 as well. (200x7=1,400+13,200=14600)

3 0
3 years ago
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