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Travka [436]
3 years ago
9

It's in the attachment. Thanks

Mathematics
1 answer:
Nina [5.8K]3 years ago
6 0

Answer:

1/3

Step-by-step explanation:

Let \frac{x}{y} =\frac{m}{n} =\frac{k}{p} =t

∴ x = yt , m = nt  and k = pt

\frac{p*y*m}{x*n*k} = \frac{p*y*nt}{yt *n*pt }=\frac{t}{t^2} = \frac{1}{t}

∴ 1/t = 3

∴ t = 1/3

∴ x = (1/3) y ⇒ y = 3x

And  n = 3m  and p = 3k

∴ \frac{x+m+k}{y+n+p} = \frac{x+m+k}{3x + 3m + 3k} = \frac{x+m+k}{3(x + m + k)} = \frac{1}{3}

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A square mirror has sides measuring 2 ft less than the sides of a square painting. If the difference between their areas is 32 f
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Answer:  The side lengths of mirror and painting are 7 ft and 9 ft respectively.

Step-by-step explanation:  Given that a square mirror has sides measuring 2 ft less than the sides of a square painting and the difference between their areas is 32 ft.

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Let x ft represents the length of the side of mirror. Then, the side length of square painting is (x+2) ft.

According to the given information, we have

\textup{area of painting}-\textup{area of mirror}=32\\\\\Rightarrow (x+2)^2-x^2=32\\\\\Rightarrow x^2+4x+4-x^2=32\\\\\Rightarrow  4x=28\\\\\Rightarrow x=\dfrac{28}{4}\\\\\Rightarrow x=7.

Therefore, the side length of mirror is 7 ft and the side length of painting is (7+2) = 9 ft.

Thus, the side lengths of mirror and painting are 7 ft and 9 ft respectively.

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