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2 years ago

It's in the attachment. Thanks

Mathematics

1 answer:

Nina [5.8K]2 years ago

6 0

Answer:

1/3

Step-by-step explanation:

Let $\frac{x}{y} =\frac{m}{n} =\frac{k}{p} =t$

∴ x = yt , m = nt and k = pt

$\frac{p*y*m}{x*n*k} = \frac{p*y*nt}{yt *n*pt }=\frac{t}{t^2} = \frac{1}{t}$

∴ 1/t = 3

∴ t = 1/3

∴ x = (1/3) y ⇒ y = 3x

And n = 3m and p = 3k

∴ $\frac{x+m+k}{y+n+p} = \frac{x+m+k}{3x + 3m + 3k} = \frac{x+m+k}{3(x + m + k)} = \frac{1}{3}$

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Use elimination to solve this system of equations <br> x-4y=11<br> 5x-7y=-10

attashe74 [19]

First, isolate x in x-4y=11 because 1 is x's coefficient.
x-4y=11
x=11+4y
Now, substitute 4y+11 for x in 5x-7y=-10.
5x-7y=-10
5(4y+11)-7y=-10
20y+55-7y=-10
Add all coefficients.
13y+55=-10
Isolate y by subtracting 55 from both sides.
13y+55=-10
13y=-10-55
13y=-65
y=-5
Now substitute -5 for y in your first equation.
x=11+4y
x=11+4(-5)
x=11-20
x=-9
Your answer would be (-9,-5).
Any questions you may have, please contact me or comment.

8 0

2 years ago

Lines CD and DE are tangent to circle A, as shown below:Lines CD and DE are tangent to circle A and intersect at point D. Arc CE

Charra [1.4K]

Answer:

55°

Step-by-step explanation:

Given that;

Lines CD and DE are tangent to circle A and intersect at point D.

and:

Arc CE measures 125 degrees. Point B lies on circle A.

There lies a diagrammatic representation below given a clear picture of what this question looks like;

If arc CE is 125°, what is the measure of ∠CDE?

SO, by using the outside angle theorem

∠CDE = $\frac{CBE-CE}{2}$

where arc CE = 125°

we can determine CBE by subtracting it from angle of a circle = 360°

Thus, CBE = 360° - 125°

CBE = 235°

Again; ∠CDE = $\frac{CBE-CE}{2}$

∠CDE = $\frac{235^0-125^0}{2}$

∠CDE = $\frac{110^0}{2}$

∠CDE = 55°

∴ The measure of ∠CDE = 55°

4 0

2 years ago

Jk,kl, and lj are all tangent to circle o, ja=13,al=7, and ck=10 what is the perimeter of angle JKL

Alex73 [517]

see the picture attached to better understand the problem

we know that

two tangent segments drawn from the same exterior point are congruent

JA=JB ,

LA=LC,

KC=KB

JA=13 units

LA=7 units

kC=10 units

hence

perimeter = JA+JB+LA+LC+KC+KB------> 13+13+7+7+10+10------> =60 units

therefore

the answer is

the perimeter of triangle JKL is 60 units

8 0

3 years ago

What percent of the area underneath<br> this normal curve is shaded?<br> the answer is not 36%

klemol [59]

Answer:

95%

Step-by-step explanation:

8 0

2 years ago

Which table represents a linear function?

Grace [21]

the table:4 represents a linear function.

What is system of linear equations?

The intersections or meetings of the lines or planes that represent the linear equations are known as the solutions of linear equations. The set of values for the variables in every feasible solution is a solution set for a system of linear equations.

Not a Solution

If there is no intersection of any lines, or if the graphs of the linear equations are parallel, then the system of linear equations cannot be solved.

An Endless Number of Options

A set of infinite points exists for which the L.H.S. and R.H.S. of an equation become equal, indicating that a system of linear equations has an infinite number of solutions.

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For table 4: The slope will be (8-6)/(3-5) = 2/-2 = -1

and (10-8)/(1-3) = 2/-2 = -1

Hence, the table:4 represents a linear function.

For a function to be linear the slope of all the segments should be same.

Learn more about system of linear equations, by the following link.

brainly.com/question/25858757

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8 0

1 year ago