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Papessa [141]
4 years ago
11

Point t is the MIDPOINT of point SV. find the location of V!

Mathematics
2 answers:
Arada [10]4 years ago
3 0

Answer:

-1.5

Step-by-step explanation:

The distance between S and T is

4 - -7

4+7 = 11

Divide this in half to find the midpoint

11/2 = 5.5

Add this to point S to get the point itself

-7 + 5.5 = -1.5

IrinaK [193]4 years ago
3 0
The location of V is 15 because from -7 to 4 is 11
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0.5% of what number is 5
Otrada [13]

Answer:

1,000

Step-by-step explanation:

5/10ths of a percent of what number is 5-which would be 1000

4 0
3 years ago
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What is the value of the expression 10 + (fraction 1 over 2)4 ⋅ 48?
EleoNora [17]
 Equation arrangement: 10 + [1/2]^4. 48
[1/2]^4 = 1/2 * 1/2 * 1/2 * 1/2 = 1/16
10 + [1/16] * 48
According to the law of BODMAS, we have to carry out multiplication operations before we carry out addition operations, therefore, we now have.
[1/16] * 48 = 3
Then, 10 +3 =13.
Thus, the final answer is 13.
5 0
3 years ago
In the diagram of circle o, what is the measure of ABC?<br> 27°<br> 54°<br> 108°<br> 120°
Vlad1618 [11]

<u>Given</u>:

Given that a circle O with two tangents BA and BC.

The major arc AC is 234°

The minor arc AC is 126°

We need to determine the measure of ∠ABC

<u>Measure of ∠ABC:</u>

We know the property that, "if a tangent and a secant, two tangents or two secants intersect in the interior of the circle, then the measure of angle formed is one half the difference of the measures of the intercepted arcs."

Hence, applying the above property, we have;

\angle ABC=\frac{1}{2}( major \widehat{AC} - minor \widehat{AC})

Substituting the values, we get;

\angle ABC=\frac{1}{2}( 234^{\circ} -126^{\circ})

\angle ABC=\frac{1}{2}( 108^{\circ})

\angle ABC=54^{\circ}

Thus, the measure of ∠ABC is 54°

Hence, Option b is the correct answer.

5 0
3 years ago
I need help on this plz thanks
kiruha [24]

Answer:

its a black screen

Step-by-step explanation:

4 0
3 years ago
What's <br><img src="https://tex.z-dn.net/?f=12%20%2B%2024%20%5Cdiv%206" id="TexFormula1" title="12 + 24 \div 6" alt="12 + 24 \d
Blababa [14]
12+24=36
36 divide by 6 is 6
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3 years ago
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