The quotient to p/q = -3 is 4
first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.
let's notice the vertex, or U-turn, is at (-2, 2)
![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-2}{ h},\stackrel{2}{ k}) \\\\\\ y=+1[x-(-2)]^2+2\implies y=(x+2)^2+2](https://tex.z-dn.net/?f=%20%5Cbf%20~~~~~~%5Ctextit%7Bparabola%20vertex%20form%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cboxed%7By%3Da%28x-%20h%29%5E2%2B%20k%7D%5C%5C%5C%5C%20x%3Da%28y-%20k%29%5E2%2B%20h%20%5Cend%7Barray%7D%20%5Cqquad%5Cqquad%20vertex~~%28%5Cstackrel%7B-2%7D%7B%20h%7D%2C%5Cstackrel%7B2%7D%7B%20k%7D%29%20%5C%5C%5C%5C%5C%5C%20y%3D%2B1%5Bx-%28-2%29%5D%5E2%2B2%5Cimplies%20y%3D%28x%2B2%29%5E2%2B2%20)
- 15
- about 94.25
- about 706.86
Lmk if you want to know how I got the answers
<span>Answer:
21 document= 1 error
120 document= 1 hour
in three and a half hours= 21 mistakes</span>
Answer:
x = 5/2
Step-by-step explanation:
Solve for x:
(5 x)/2 = 25/4
Hint: | Multiply both sides by a constant to simplify the equation.
Multiply both sides of (5 x)/2 = 25/4 by 2/5:
(2×5 x)/(5×2) = 2/5×25/4
Hint: | Express 2/5×5/2 as a single fraction.
2/5×5/2 = (2×5)/(5×2):
(2×5)/(5×2) x = 2/5×25/4
Hint: | Express 2/5×25/4 as a single fraction.
2/5×25/4 = (2×25)/(5×4):
(2×5 x)/(5×2) = (2×25)/(5×4)
Hint: | Cancel common terms in the numerator and denominator of (2×5 x)/(5×2).
(2×5 x)/(5×2) = (5×2)/(5×2)×x = x:
x = (2×25)/(5×4)
Hint: | In (2×25)/(5×4), divide 25 in the numerator by 5 in the denominator.
25/5 = (5×5)/5 = 5:
x = (2×5)/4
Hint: | In (2×5)/4, divide 4 in the denominator by 2 in the numerator.
2/4 = 2/(2×2) = 1/2:
Answer: x = 5/2
