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Pie
3 years ago
10

2. A pizza restaurant charges y amount for a pizza based on the x number of toppings you select. What

Mathematics
1 answer:
Lapatulllka [165]3 years ago
5 0

Answer:

slope should be 1.50x and your y-intercept should be 7.50

Step-by-step explanation:

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If x=3 calculate the value of x3-x
Dmitrij [34]
x^3-x=3^3-3= \\\\ =27-3= \\\\ =\boxed{24}
6 0
3 years ago
Read 2 more answers
Kiran got 99 marks in Math, 69 mark in English and 91 in science. Another student Surya got 92 marks in Maths 33 in English and
statuscvo [17]

Answer:

Total marks = 468

Step-by-step explanation:

to find their total marks, you should simply find the sum of all the marks scored by Kiran and Surya in all subjects. That is done as follows:

99 + 69 + 91 + 92 + 33 + 84 =  468

4 0
3 years ago
This is my last question please help ​
Nina [5.8K]

Answer:

N

Step-by-step explanation:

I hope this helps!!

6 0
3 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
In AJKL, the measure of ZL=90°, the measure of ZJ=18°, and KL = 6.1 feet. Find the
bija089 [108]

Answer:

JK= 19.7 feet

Step-by-step explanation:

We are given with a right triangle because m<L =90 degrees. Let's use the trigonometric ratio to solve for JK.

7 0
3 years ago
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