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2 answers:
Answer:
The closest number of juniors and seniors who were inducted is 69.
Step-by-step explanation:
At Lincoln High School, approximately 7% of enrolled juniors and 5% of enrolled seniors were inducted into the National Honor Society last year.
There were 562 juniors and 602 seniors enrolled at Lincoln High School last year.
We will calculate the number of students as:
=
= 69.44
Therefore, the closest number of juniors and seniors who were inducted is 69.
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Factor the following:
4 p (4 p - 1) - 3 (4 p - 1)^2
Factor 4 p - 1 from 4 p (4 p - 1) - 3 (4 p - 1)^2:
(4 p - 1) (4 p - 3 (4 p - 1))
-3 (4 p - 1) = 3 - 12 p:
(4 p - 1) (4 p + 3 - 12 p)
Grouping like terms, 4 p - 12 p + 3 = 3 + (4 p - 12 p):
(4 p - 1) (3 + (4 p - 12 p))
4 p - 12 p = -8 p:
Answer: (4 p - 1) (-8 p + 3)
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Factor the following:
m (m + n) - 3 m (m + n)^2
Factor m + n out of m (m + n) - 3 m (m + n)^2, resulting in (m + n) (m - 3 m (m + n)^(2 - 1)):
(m + n) (m - 3 m (m + n)^(2 - 1))
2 - 1 = 1:
(m + n) (m - 3 m (m + n))
Factor m out of m - 3 m (m + n), resulting in m (1 - 3 (m + n)):
m (1 - 3 (m + n)) (m + n)
-3 (m + n) = -3 m - 3 n:
Answer: m (m + n) (-3 m - 3 n + 1)
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Factor the following:
6 u^2 (2 u - 5)^2 - 12 u^2 (2 u - 5) (u + 5)
Factor u^2 out of 6 u^2 (2 u - 5)^2 - 12 u^2 (2 u - 5) (u + 5), resulting in u^2 (6 (2 u - 5)^2 - 12 (2 u - 5) (u + 5)):
u^2 (6 (2 u - 5)^2 - 12 (2 u - 5) (u + 5))
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u^2 (6 4 u^2 - 20 u + 25 - 12 (2 u - 5) (u + 5))
6 (4 u^2 - 20 u + 25) = 24 u^2 - 120 u + 150:
u^2 (24 u^2 - 120 u + 150 - 12 (2 u - 5) (u + 5))
(u + 5) (2 u - 5) = (u) (2 u) + (u) (-5) + (5) (2 u) + (5) (-5) = 2 u^2 - 5 u + 10 u - 25 = 2 u^2 + 5 u - 25:u^2 (150 - 120 u + 24 u^2 - 122 u^2 + 5 u - 25)
-12 (2 u^2 + 5 u - 25) = -24 u^2 - 60 u + 300:
u^2 (-24 u^2 - 60 u + 300 + 24 u^2 - 120 u + 150)
Grouping like terms, 24 u^2 - 24 u^2 - 60 u - 120 u + 150 + 300 = (-120 u - 60 u) + (24 u^2 - 24 u^2) + (150 + 300):
u^2 ((-120 u - 60 u) + (24 u^2 - 24 u^2) + (150 + 300))
-120 u - 60 u = -180 u:
u^2 (-180 u + (24 u^2 - 24 u^2) + (150 + 300))
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u^2 (-180 u + (24 u^2 - 24 u^2) + 450)
24 u^2 - 24 u^2 = 0:
u^2 (450 - 180 u)
Factor 90 out of 450 - 180 u:
Answer: u^2×90 (5 - 2 u)
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4 p (4 p - 1) - 3 (4 p - 1)^2
Factor 4 p - 1 from 4 p (4 p - 1) - 3 (4 p - 1)^2:
(4 p - 1) (4 p - 3 (4 p - 1))
-3 (4 p - 1) = 3 - 12 p:
(4 p - 1) (4 p + 3 - 12 p)
Grouping like terms, 4 p - 12 p + 3 = 3 + (4 p - 12 p):
(4 p - 1) (3 + (4 p - 12 p))
4 p - 12 p = -8 p:
Answer: (4 p - 1) (-8 p + 3)
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m (m + n) - 3 m (m + n)^2
Factor m + n out of m (m + n) - 3 m (m + n)^2, resulting in (m + n) (m - 3 m (m + n)^(2 - 1)):
(m + n) (m - 3 m (m + n)^(2 - 1))
2 - 1 = 1:
(m + n) (m - 3 m (m + n))
Factor m out of m - 3 m (m + n), resulting in m (1 - 3 (m + n)):
m (1 - 3 (m + n)) (m + n)
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Answer: m (m + n) (-3 m - 3 n + 1)
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Factor the following:
6 u^2 (2 u - 5)^2 - 12 u^2 (2 u - 5) (u + 5)
Factor u^2 out of 6 u^2 (2 u - 5)^2 - 12 u^2 (2 u - 5) (u + 5), resulting in u^2 (6 (2 u - 5)^2 - 12 (2 u - 5) (u + 5)):
u^2 (6 (2 u - 5)^2 - 12 (2 u - 5) (u + 5))
(2 u - 5) (2 u - 5) = (2 u) (2 u) + (2 u) (-5) + (-5) (2 u) + (-5) (-5) = 4 u^2 - 10 u - 10 u + 25 = 4 u^2 - 20 u + 25:
u^2 (6 4 u^2 - 20 u + 25 - 12 (2 u - 5) (u + 5))
6 (4 u^2 - 20 u + 25) = 24 u^2 - 120 u + 150:
u^2 (24 u^2 - 120 u + 150 - 12 (2 u - 5) (u + 5))
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-12 (2 u^2 + 5 u - 25) = -24 u^2 - 60 u + 300:
u^2 (-24 u^2 - 60 u + 300 + 24 u^2 - 120 u + 150)
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u^2 ((-120 u - 60 u) + (24 u^2 - 24 u^2) + (150 + 300))
-120 u - 60 u = -180 u:
u^2 (-180 u + (24 u^2 - 24 u^2) + (150 + 300))
150 + 300 = 450:
u^2 (-180 u + (24 u^2 - 24 u^2) + 450)
24 u^2 - 24 u^2 = 0:
u^2 (450 - 180 u)
Factor 90 out of 450 - 180 u:
Answer: u^2×90 (5 - 2 u)
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