Determine whether the recursive sequence defined by an =1 , an+1 = 5+an diverges or converges. Find the limit if it converges.

Answer this pleaseee !!

photoshop1234 [79]

Answer:

D.

Step-by-step explanation:

m<F = m<B - Corresponding Angles Theorem

m<B + m<A = 180 - Adjacent Angles Theorem

180 - 105 = m<A

75 = m<A; therefore, m<A = 75.

6 0

2 years ago

Read 2 more answers

1. The scale of a map is 1 in = 19.5 mi map: ________ in actual: 9.5 mi 2. The scale of a map is 7 in = 16 mi map: 4.9 in actual

alexandr402 [8]

We use ratio and proportion to solve each of these:

1. The scale of a map is 1 in = 19.5 mi map: ________ in actual: 9.5 mi
1 in / 19.5 mi = x in / 9.5 mi, x = 0.487 in

2. The scale of a map is 7 in = 16 mi map: 4.9 in actual: ______ mi
7 in / 16 mi = 4.9 in / x mi, x = 11.2 mi

3. The scale factor for a model is 5 cm = ________ m Model : 72.5 cm actual: 165.3 m
5 cm / x m = 72.5 cm / 165.3 m, x = 11.4 m

4. The scale of a map is 1 in = 9.6 mi map: ________ in actual: 34.7 mi
1 in / 9.6 mi = x in / 34.7 mi, x = 3.62 in

5. The scale of a map is 1 ft = 9.6 mi map: ________ ft actual: 38.4 mi
1 ft / 9.6 mi = x ft / 38.4 mi, x = 4 ft

6. The scale factor for a model is 5 cm = ________ m Model : 22.4 cm actual: 155.2 m
5 cm / x m = 22.4 cm / 155.2 m, x = 34.64 m

7. The scale of a map is 5 in = 10 mi map: 8.7 in actual: ______ mi
5 in / 10 mi = 8.7 in / x mi, x = 17.4 mi

8. The scale of a map is 1 in = 13.5 mi map: ________ in actual: 65.9 mi
1 in / 13.5 mi = x in / 65.9 mi, x = 4.88 in

9. The scale factor for a model is 5 cm = ________ m Model : 61.5 cm actual: 143.2 m
5 cm / x m = 61.5 / 143.2 m, x = 11.64 m

10. The scale factor for a model is 5 cm = ________ m Model : 29.7 cm actual: 179.5 m
5 cm / x m = 29.7 cm / 179.5 m, x = 30.22 m

3 0

3 years ago

Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi

boyakko [2]

Answer:

lower limit =0.261

upper limit =0.369

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Description in words of the parameter p

$p$ represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

n=200 is the sample size required

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that have experienced bullying

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.