Answer:
A) The minimum required diameter of the brass shaft D₁ = 0.00176 m
B) The minimum required diameter of the aluminium shaft D₂ = 0.00142 m
Step-by-step explanation:
<u>Data:</u>
A compound shaft has two segments made of brass and aluminium
Allowable shear stress of Brass = 69 MPa.
allowable sheer stress of Aluminium = 86 MPa.
Torque TC = 23900 N-m
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<u>Find</u>: Minimum required diameter of the brass D₁ and Auminium D₂
<u>Solution</u>: see attached picture for workings that shows the break down of the minimum diameter for each segment of the shaft.
Step by step:
Each day it takes a sample of 15 pies - on Monday he needed 4:
4/15 = x/450 (450 being the total for each day)
4 x 450 = 1800
1800 divided by 15 = 120
120 is the amount of pies that were made on Monday
Hope this helps
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How to find the complementary angle:
90-41.1=
how to find the supplementary angle:
180-41.1=
11. P=[2(x+y)]3 = 6(x+y) or 6x+6y
12.A=(x+3)(y+3) or xy+ 3x + 3y + 9
Answer:
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Step-by-step explanation: