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zlopas [31]
3 years ago
9

What is 6-y=-2 in y=mx+b form?

Mathematics
1 answer:
Alona [7]3 years ago
6 0

Answer:

y = 0x +8

Step-by-step explanation:

6-y=-2

subtract 6 from each side

6-y-6=-2-6

-y = -8

multiply by -1

y = 8

y = 0x +8

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Simplify the expression (-7)2.<br><br><br>-14<br><br>49<br><br>-49<br><br>14<br>OwO
MissTica

Answer:

-14

Step-by-step explanation:

-7*2= -14

8 0
3 years ago
Read 2 more answers
Five less than 6 times a number is equivalent to 1 less than twice that number?
Bad White [126]

Answer:

No

Step-by-step explanation:

5 × 6 = 30 - 5 = 25

5 × 2 = 10 - 1 = 9

5 0
3 years ago
Read 2 more answers
I really need help I’m very confused
Vaselesa [24]

Answer:

10: -11n^5

12: 6k^2 -6k+7

Step-by-step explanation:

Ok so what your gonna do is add or subtract the ones with the same exponent.

so -15+4= -11 since they are both n^5 you can add them so your answer is:

-11n^2

now you have 8k^2-k-5k+7-2k. so you are gonna rearrange them so the same exponents are together.(keep the sign in front in front, if no sign it is positive)

8k^2-2k^2-5k-k+7

add like exponents

6k^2-6k+7

6 0
3 years ago
3. The following sets are not equal - An (BUC) and AU(BnC) Construct a universe U and non-empty sets A, B, and C so that the abo
yarga [219]

Answer:

1.U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

2.U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

Step-by-step explanation:

We are given that A\cap (B\cup C) and A\cup (B\cap C)

are different sets

1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same

Suppose U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

B\cap C=\phi

B\cup C={2,3,4,5}

A\cap (B\cup C)={2}\cap{2,3,4,5}={2}

A\cup (B\cap C)={2}\cup\phi={2}

Hence, A\cap (B\cup C)=A\cup (B\cap C)

2.We have to construct a universe set U and non empty sets A,B and C so that  above sets are in fact different

Suppose U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

B\cap C=\phi

B\cup C={2,3,4}

A\cup (B\cap C)={1,2}\cup \phi={1,2}

A\cap (B\cup C)={1,2}\cap {2,3,4}={2}

Hence, A\cap (B\cup C)\neq A\cup (B\cap C)

3 0
3 years ago
The researcher has limited resources. He sends 9 emails from a Latino name, and 14 emails from a non-Latino name. For the Latino
deff fn [24]

Answer: 38.41 minutes

Step-by-step explanation:

The standard error for the difference in means is given by :-

SE.=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2}}

where , \sigma_1 = Standard deviation for sample 1.

n_1= Size of sample 1.

\sigma_2 = Standard deviation for sample 2.

n_2= Size of sample 2.

Let the sample of Latino name is first and non -Latino is second.

As per given , we have

\sigma_1=82

n_1=9

\sigma_2=101

n_2=14

The standard error for the difference in means will be :

SE.=\sqrt{\dfrac{(82)^2}{9}+\dfrac{(101)^2}{14}}

SE.=\sqrt{\dfrac{6724}{9}+\dfrac{10201}{14}}

SE.=\sqrt{747.111111111+728.642857143}

SE.=\sqrt{1475.75396825}=38.4155433158\approx38.41

Hence, the standard error for the difference in means =38.41 minutes

3 0
3 years ago
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