Trigonometric area formula: Area = What is the area of triangle PQR? Round to the nearest tenth of a square unit. 70.5 square un
its 111.3 square units 185.4 square units 222.5 square units
2 answers:
The complete question in the attached figure
we know that
When we know <span>two sides and the included angle the formula for calculate the area is
</span>Area=(1/2)*a*b*sin C
in this problem
let
a=20
b=12
C=68°
Area=(1/2)*20*12*sin 68°------> Area=111.26 units²-----> Area=111.3 units²
the answer is
111.3 units²
we know that
When we know <span>two sides and the included angle the formula for calculate the area is
</span>Area=(1/2)*a*b*sin C
in this problem
let
a=20
b=12
C=68°
Area=(1/2)*20*12*sin 68°------> Area=111.26 units²-----> Area=111.3 units²
the answer is
111.3 units²
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Answer:
<h2>√34sin(x + 0.33π)</h2>Step-by-step explanation:
The general form of the equation acosx + bsinx = Rsin(x + e) where R is the resultant of the constants 'a' and 'b' and e is the angle between them.
R = √a²+b²
Given the function f(x) = 3 cos x + 5 sin x, comparing with the general equation;
a = 3, b = 5
R = √3²+5²
R = √9+25
R =√34
in radians;
3 cos x + 5 sin x = √34sin(x + 0.33π)