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Andru [333]
3 years ago
9

Trigonometric area formula: Area = What is the area of triangle PQR? Round to the nearest tenth of a square unit. 70.5 square un

its 111.3 square units 185.4 square units 222.5 square units

Mathematics
2 answers:
larisa [96]3 years ago
8 0

Answer:

111.3 square units

Step-by-step explanation:

Natalija [7]3 years ago
3 0
The complete question in the attached figure

we know that
When we know <span>two sides and the included angle the formula for calculate the area is
</span>Area=(1/2)*a*b*sin C
in this problem
let
a=20
b=12
C=68°
Area=(1/2)*20*12*sin 68°------> Area=111.26 units²-----> Area=111.3 units²

the answer is
111.3 units²

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5 0
3 years ago
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Answer:

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3 0
2 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

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5 0
3 years ago
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jekas [21]
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How do you do this? Well, let's get rid of that pesky negative ten, shall we?
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8 0
3 years ago
Read 2 more answers
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valkas [14]

Answer:

1

Step-by-step explanation:

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2 years ago
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