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Marina86 [1]
4 years ago
15

a few years ago, melky bought 100 shares of a cologne company's stock for $16.77 per share. Last month she sold all of the share

s for $11.88 per share. What was her loss?
Mathematics
2 answers:
garik1379 [7]4 years ago
3 0
$489
$16.77*100
-
$11.88*100
=$489
Taya2010 [7]4 years ago
3 0

Answer:

$489.

Step-by-step explanation:

We have been given that a few years ago, Melky bought 100 shares of a cologne company's stock for $16.77 per share. Last month she sold all of the shares for $11.88 per share.

First of all, we will find the difference of purchase price of per share and selling price of per share.

\text{Loss per share}=\$16.77-\$11.88

\text{Loss per share}=\$4.89

\textMelky's loss}=\$4.89\times 100

\textMelky's loss}=\$489

Therefore, Melky lost $489 in total.

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Rich deposited money into a bank account that earned 2.5% simple interest each year. After 2 years, he had earned $14.65 in inte
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we know that


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P=\$293


therefore

<u>the answer is</u>

\$293




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3 years ago
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fiasKO [112]
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3 0
3 years ago
A 4 metre ladder is placed against a vertical wall.
Black_prince [1.1K]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

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0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

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