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SpyIntel [72]
3 years ago
9

కమలములు నేటీనీ విడిచి పేటీ బయటకి వస్తే ఎం జరుగుతుంది​

Mathematics
2 answers:
Neporo4naja [7]3 years ago
6 0

Answer:

లోటస్ మొక్కలకు సూపర్హైడ్రోఫోబిక్ ఉపరితలాలు ఉంటాయి. వాటిపై పడే నీటి చుక్కలు పూస మరియు బోల్తా పడతాయి. ఈ ఆకులు పొడిగా ఉండటమే కాదు, బిందువులు చుట్టుముట్టేటప్పుడు చిన్న చిన్న ధూళి కణాలను తీస్తాయి, తద్వారా తామర ఆకులు కూడా స్వీయ శుభ్రంగా ఉంటాయి.

Step-by-step explanation:

Hopes this helps

Murljashka [212]3 years ago
3 0

Answer:

లోటస్ సరస్సులు మరియు నదులలో పెరిగే మొక్క. పువ్వులు, విత్తనాలు, ఆకులు మరియు భూగర్భ కాండం (రైజోమ్) యొక్క భాగాలు make షధ తయారీకి ఉపయోగిస్తారు

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Please help need it asap
Studentka2010 [4]

Answer:

195

Step-by-step explanation:

87+38+40=165

360-165=195

Hope this helps!

If not, I am sorry.

4 0
2 years ago
A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
(3x - 1)+(x ^ 2 + 5x - 4)
RideAnS [48]

Answer: if it is simply then  the answer is 3x^3+14x^2-17x+14

         

Step-by-step explanation:

5 0
4 years ago
WILL MARK BRAINLIEST IF CORRECT
Anon25 [30]

Answer:

A B and E

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLS HELP ME.
yarga [219]

Answer:

15092cm^3

Step-by-step explanation:

The total thickness of the strip of metal sheet  would be 2*10=20cm

the new radius of the cylinder would be 9/2+20=24.5cm

Volume of a cylinder: ((pi)r^2)h

the height is 8cm

Volume : (22/7)*24.5^2*8

=15092cm^3

7 0
3 years ago
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