Radius of the rings = 10 / 2 = 5 cm 0.05m
Distance between them D = 15 cm = 0.15 m
The charge of left ring is Ql = -20 x 10^-9 C
The charge of right ring is Qr = 20 x 10^-9 C
Since it the electric field at the midpoint, it is same for both rings and the there are opposite charges the electric filed will be sum of electric field of both charges.
Electric field on the left El = (k x Ql) / (D/2)^2 = (4 x k x Ql) / D^2
Electric field on the Right Er = (k x Qr) / (D/2)^2 = (4 x k x Qr) / D^2
Electric field E = El + Er = ((4 x k x Ql) / D^2) + ((4 x k x Qr) / D^2)
E = 4k/ D^2 (Ql + Qr); k is Coulombs constant = 8.99 x 10^9 Nm2Câ’2
E = 4 x 8.99 x 10^9/ 0.15^2 (2n + 2n) = 1598 x 10^9 x 4 x 10^-9 = 6393 N/c
Force f = E x q, q being the charge at the mid point
Force = q x 6393 N/c = 6.393q x 10^3 N
Answer:
The cell will have no electromotive force in it.
Explanation:
The battery provides the chemical energy that produces the force needed to move electron around the circuit and to generate electrical energy.
- electrochemical cells are devices in which chemical reactions produce electric current.
- The electromotive force inherent in a cell provides the driving force for the current to flow.
- Without this force, there would not be enough energy to move the electrons.
Answer:
1 / 5.587 is equal to 0.179 kg/m³
Hope it helps:)