Two or three i believe to be the answer
Answer:
44.5s ; 22.64 m/s
Explanation:
The motion of the truck could be separated into 3 different phases :
First :
Time of motion :
Initial Velocity, u = 0 ; final velocity, v = 29 m/s
Acceleration, a = 2 m/s²
Recall: acceleration = change in velocity / time
Time = change in velocity / acceleration
Time = (29 - 0) / 2 = 14.5 second
Distance traveled = ((29 + 0) /2) * 14.5 = 210.25 m
Second :
Time = 25 seconds at constant speed
29 m/s for 25 seconds
v*t = 29 * 25 = 725 m
Third:
5 seconds before coming to rest
((29 + 0) /2) * 5
14.5 * 5 = 72.5 m
A.)
Length of journey = (14.5+ 25 + 5) = 44.5 seconds
B.)
Average velocity = total distance / total time taken
Average velocity = (210.25 + 725 + 72.5) / 44.5
= 1007.75 / 44.5
= 22.646067
= 22.64 m/s
I can't think of any way that pressure can be decreased due to added pressure.
Be that as it may, and it certainly still is ...
No matter what you do to the pressure or the temperature of
the gas in that tank, the volume doesn't change. Any sample
of gas always expands to fill the container in which it's confined.
Its volume doesn't change until you either transfer it to another
container with different volume, or else change the volume of
the container it's in.
Can you complete the question...
