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irinina [24]
4 years ago
9

Which condition is necessary for a standing wave?

Physics
1 answer:
mezya [45]4 years ago
3 0
What are the conditions?
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In Figure 10.13, the author illustrates a book being raised at constant speed. Which of the following statements are true? Selec
sergey [27]

The true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

We have to note that from the law of conservation of mechanical energy, the sum of the kinetic and potential energy of the book at any point remains constant.

If the book is being raised at constant speed, the the true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

Learn more about kinetic energy: brainly.com/question/15308590

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2 years ago
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Which tool would you use to measure the height of a cube of metal
SCORPION-xisa [38]
It depends on the size of the cube, but you could use a ruler for almost any size, or if it is small enough, you could use a caliper to get a very precise measurement.
3 0
3 years ago
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Far from any other masses, two masses, m1 and m2, are interacting gravitationally. The value for the mass of m1 suddenly doubles
NNADVOKAT [17]
<span>It also doubles The gravitational force between two masses is expressed as: F = G*m1*m2/r^2 where F = Force between the two masses m1 = Mass of object 1 m2 = Mass of object 2 r = distance between centers of object 1 and object 2 G = Gravitational constant The exact values of G, m1, m2, and r don't matter since all except for m1 is held constant. And when m1 suddenly doubles, the force attracting the two object to each other also doubles.</span>
5 0
4 years ago
Which type of rock can only form below earths surface?
Inessa [10]

Answer: Igneous it forms because of magma but magma is under the earths surface so its Igneous

Explanation:

7 0
2 years ago
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A student lifts a 50 pound (lb) ball 4 feet (ft) in 5 seconds (s). How many joules of work has the student completed?
Elis [28]

           Work = (weight) x (distance)

  Work = (50 lb) x (1 kg / 2.20462 lb) x (9.81 newton/kg)

                           x (4 feet) x (1 meter / 3.28084 feet)

           = (50 x 9.81 x 4) / (2.20462 x 3.28084)  newton-meter

           =        271.3 joules .

We don't need to know how long the lift took, unless we
want to know how much power he was able to deliver.

                   Power = (work) / (time)    

                               = (271.3 joule) / (5 sec)  =  54.3 watts .
________________________________________

The easy way:

         Work = (weight) x (distance)

                
  = (50 pounds) x (4 feet)  =  200 foot-pounds

Look up (online) how many joules there are in 1 foot-pound.

There are  1.356 joules in 1 foot-pound.

So  200 foot-pounds = (200 x 1.356) = 271.2 joules.

That's the easy way.
5 0
3 years ago
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