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3 years ago

If cos theta is less than 0 and cot theta is greater than 0, then the terminal point determined by theta is in:

Mathematics

2 answers:

kirill115 [55]3 years ago

8 0

Answer:

<h2>B. Quadrant 3</h2>

Step-by-step explanation:

Look at the picture.

Keith_Richards [23]3 years ago

5 0

There exist an abbreviation that ALL - S - T - C where all trigonometric functions in first quandrant are positive. S, T, and C are the first letters of the trigonometric functions that are positive in quadrant 2, 3, and 4, respectively. This also means that in the same quadrant, their reciprocals are also positive. For the given above, it is in Quadrant 3 where T is positive and cosine is negative.

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Determine the equation of the line that passes through the given points. (If you have a graphing calculator, you can use the tab

siniylev [52]

Answer:

y = -2x

Step-by-step explanation:

It passes through -5, 10 and 5, -10

gradient = Δy/Δx

gradient = -10 - 10 / 5 -- 5

gradient = -20 / 10

gradient = -2

let's use -5, 10 for y = mx + b

10 = -2(-5) + b

10 = 10 + b

b = 10 - 10

b = 0.

the equation of the line is just y = -2x

6 0

2 years ago

6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP

adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = $360^{o}$ - $324^{o}$

= 0 $36^{o}$

Sum of angles in a triangle = $180^{o}$

<P + <Q + <S = $180^{o}$

048° + 0 $36^{o}$ + <S = $180^{o}$

$84^{o}$ + <S = $180^{o}$

<S = $180^{o}$ - $84^{o}$

= $96^{o}$

<S = $96^{o}$

Applying the Sine rule,

$\frac{y}{Sin P}$ = $\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin P}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin 48^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{y}{0.74314}$ = $\frac{17}{0.99452}$

⇒ y = $\frac{12.63338}{0.99452}$

= 12.703

y = 12.70 km

$\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{x}{Sin 36^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{x}{0.58779}$ = $\frac{17}{0.99452}$

⇒ x = $\frac{9.992430}{0.99452}$

= 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

6 0

3 years ago

What is the missing dimension of a parallelogram if h=5 1/4feet and A=12feet

alexandr1967 [171]

The missing is the base
A=bh
12= 5.25b
Divide both sides by 5.25
b=2.29 ft

3 0

3 years ago

Nia plans to put enough money in the bank each week for 100 weeks so that the amount in the bank is always proportional to the w

kobusy [5.1K]

Nia will have $250 in the savings account

6 0

3 years ago

Read 2 more answers

What are the coordinates of the point on the directed line segment from (-6, -6)(−6,−6) to (9, -1)(9,−1) that partitions the seg

GrogVix [38]

Answer:

(0, -4)

Step-by-step explanation:

The coordinates of the points from which the directed line segment extends = (-6, -6) to (9, -1)

The ratio the required point partitions the line = 2 to 3

The formula for finding the coordinate of a point that partitions a line AB into a ratio 'a' to 'b', where the coordinates of, A = (x₁, y₁) and B = (x₂, y₂) is given as follows;

$\left(\dfrac{a}{a + b} \times (x_1 - x_2)+ x_1, \ \dfrac{a}{a + b} \times (y_1 - y_2)+ y_1 \right)$

Therefore, the required point is located as follows;

$\left(\dfrac{2}{2 + 3} \times (9 - (-6))+ (-6), \ \dfrac{2}{2 + 3}\times (-1 - (-6))+ (-6) \right) = (0, -4)$

The coordinates of the point is (0, -4)

6 0

3 years ago