Answer:
Area of rectangle: 256
Area of triangle 1: 24
Area of triangle 2: 16
Area of triangle 3: 96
Area of trapezoid: 120
Step-by-step explanation:
I just did the question on the thing so Ik I'm right.
-The graph measures by twos. To get the area of the rectangle get the base times height of it. That would be 16x16=256.
-Get base (8) times height (6) of triangle 1 then divide by 2, remember to count the squares by 2 for finding all areas. The formula would be 1/2(b)(h) because dividing by 2 is the same as multiplying times 1/2. Plug it in and (8)(6)=48 then divide by 2 which equals 24.
-Same formula for triangle 2. Plug it in and (8)(4)=32 and divide by 2 and it equals 16.
-Same formula for triangle 3. Plugged in is (12)(16)=192 divide by 2 and it equals 96.
-To find the area of the trapezoid get your rectangle area (256) and subtract all the triangle areas. So 256 - 6 - 16 - 96 = 120.
Answer:
<em>The observed t (2.533) is in the tail cut off by the critical t (2.462), therefore we reject H0. It is likely that the books are older than 20 years of age on average.</em>
Step-by-step explanation:
<em>Step 1: Hypotheses and α level
</em>
H0: μ ≤ 20
H1: μ > 20
<u><em>α = 0.01</em></u>
<em>Step 2: Critical region
</em>
α = .01
One-tailed
df = n – 1 = 30 – 1 = 29
<u><em>t - critical = 2.462
</em></u>
<em>Step 3: Calculate t which is observed
</em>
sM = √(s2 / n) = √(67.5 / 30) = 1.5
t = (M – μ) / sM
t = (23.8 – 20) / 1.5
<u><em>t = 2.533
</em></u>
<u><em /></u>
Multiply both sides by 2pi:
F(2pi) = sqrt(g/l)
Square both sides:
F^2 (2pi)^2 = g/l
Solve for l by dividing both sides by F^2 (2pi)^2
L = g/ F^2 (2pi)^2
Simplify:
L = g / 4pi^2(f^2)
:-):-):-):-):-)
Step-by-step explanation:
1) 40÷10
2) 40÷2
Answer:
Step-by-step explanation:
Base for the exponent and for the logarithm are the same!
10^0 is the <u>exponential</u> form where 10 is the base and 0 the exponent
is the l<u>ogarithm</u> form where 10 is the base
To solve 
ask the question :
To what power should I raise the base 10 to obtain the number 1 ?
The answer to the power 0 therefore
