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masya89 [10]
3 years ago
5

The base of an exponential function cannot be a negative number true or false

Mathematics
2 answers:
aliya0001 [1]3 years ago
6 0
True. It can be negative. Then it would not be continuous; think about what if the exponent was fractional.
Valentin [98]3 years ago
3 0

Answer:

True

Step-by-step explanation:

Given statement : The base of an exponential function cannot be a negative number.

We need to check whether the given statement is true or not.

The general form of an exponential function is

f(x)=ab^x

where, a is the initial value and b is the base of exponential function.

The value of base b is always greater than 0 because

1. The terms like (-3)^\frac{1}{2} is an imaginary number and it make no sense. So, the base of an exponential function cannot be a negative number.

2. It b=0, then (0)^x=0, which is a constant function. So, the base of an exponential function cannot be 0.

It means b>0.

Therefore, the given the given statement is true.

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Answer:

6, 7, and 8

Step-by-step explanation:

2x/3 + 7 <u>></u> 11

Subtract 7 from both sides

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Convert to scientific notation ​
andreev551 [17]

Answer:

8.245*10^6

Step-by-step explanation:

scientific notation is known as c*10^n

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NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

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We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

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Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

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Then:

c  = 2d = 2*(-1) = -2

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So the values are:

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  • a = -1
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  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

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