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masya89 [10]
4 years ago
5

The base of an exponential function cannot be a negative number true or false

Mathematics
2 answers:
aliya0001 [1]4 years ago
6 0
True. It can be negative. Then it would not be continuous; think about what if the exponent was fractional.
Valentin [98]4 years ago
3 0

Answer:

True

Step-by-step explanation:

Given statement : The base of an exponential function cannot be a negative number.

We need to check whether the given statement is true or not.

The general form of an exponential function is

f(x)=ab^x

where, a is the initial value and b is the base of exponential function.

The value of base b is always greater than 0 because

1. The terms like (-3)^\frac{1}{2} is an imaginary number and it make no sense. So, the base of an exponential function cannot be a negative number.

2. It b=0, then (0)^x=0, which is a constant function. So, the base of an exponential function cannot be 0.

It means b>0.

Therefore, the given the given statement is true.

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Simplify 2^-6 times 2^3
IgorC [24]

Answer:

(2^-6)*(2^3)

=2^(-6+3)

=2^-3

=1/(2^3)

=1/8

3 0
3 years ago
Read 2 more answers
Find the missing side lengths. Leave your answers in simplest radical form.
saveliy_v [14]
ANSWER:
d. x = 15, y= 15√3

EXPLANATION:
This is a special triangle, more specifically a 30-60-90 degree triangle. For sake of not confusing x and y, we will use z to use as our reference for solving this triangle. The side lengths for each angle are as follows:
• 60 degrees = z√3
- this is the value for your y answer
• 30 degrees = z
- this is the value for your x answer
• Hypotenuse = 2z
- this is what we already have

We solve for what we already have which is the Hypotenuse = 30:
2x = 30
x = 15

We now have our x value which is 15.
Now we just plug in that x value for every expression for every angle.

x = 15
y = 15√3

Sorry if I explained it too thoroughly but I’ll be glad to answer any questions or clarifications



8 0
3 years ago
PLZ Help
o-na [289]
I have This too sooo hard
5 0
3 years ago
3. A car starts from rest and accelerates uniformly over a time of 6.21 seconds
Klio2033 [76]

We have,

t = 6.21 s

s = 111 m

u = 0 m/s

To determine: "a" of the particle.

We know,

s = ut + ½ at²

⇒ s = ½ at²

⇒ a = 2s/t²

⇒ a = [2(111 m)]/(6.21 s)²

⇒ a = (222 m)/(38.5641 s²)

⇒ a ≈ 5.75 m/s²

5 0
3 years ago
Please Help See Attached Pic
olga2289 [7]
Letter A is the answer
7 0
4 years ago
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