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3 years ago

∠C and ∠D are vertical angles with m∠C=−2x+90 and m∠D=x−30 . What is m∠D ?

1 answer:

5 0

∠C = ∠ D (vertical angles

C= -2x + 90
D= x-30

Since C = D , Then -2x + 90 = x-30

-2x - x = - 30 - 90

-3x = -120

3x = 120 and x = 40°. Now replace x by 40 in any of the equality, say :
D = x-30 ; D = 40 - 30 and D = 10°

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Answer:

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Step-by-step explanation:

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4 years ago

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Dmitrij [34]

Answer:

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3 years ago

How to factor 5m2-29m+20?

ser-zykov [4K]

Question :

5m^2 - 29m + 20

Steps:

What can u factor to get 20?

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(5m^2 - 4m) + (-25m + 20)

*Factor out m from (5m^2 - 4m) : m(5m - 4)

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= (5m - 4)(m - 5) <======= Answer

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3 years ago

if a motercycle is moving at a constant speed down the highway of 40 km/hr, how long would it the motorcycle to travel 10 km

ahrayia [7]

Answer:

15 minutes

Step-by-step explanation:

First, the motorcycle goes at a speed of 40 km/hr.

The question asks for how long it would take to travel 10 km.

Well, there are 60 minutes in an hour, since we will be translating into minutes.

Also, 10 km is 1/4 of 40 km, so it would make sense that the time length would be 1/4 of an hour as well.

1/4 of 60 minutes is 15 minutes. So it takes 15 minutes for the motorcycle to travel 10 km.

Now, if all this wordy stuff is too much to comprehend, you can also solve using proportional relationships.

$\frac{40km}{60min}=\frac{10km}{xmin}$

Now cross multiply:

$40km*xmin=10km*60min\\40x=600$

Divide both sides by 40:

$\frac{40x}{40}=\frac{600}{40}\\x=15$

Again, this shows that it wouls take 15 minutes for the motorcycle to travel 10 km.

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3 years ago

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3 years ago

∠C and ​ ∠D ​ are vertical angles with m∠C=−2x+90 and m∠D=x−30 . What is m∠D ?

∠C and ∠D are vertical angles with m∠C=−2x+90 and m∠D=x−30 . What is m∠D ?