2 years ago

Find x if a] 5^x=625 root 5 b] 3^2x-1 = 243

1 answer:

6 0

x=3, you can find this by using finding common bases for equation b because 243=3^5. Because of that you can get rid of three on both sides to get the equation 2x-1=5 and then just solve for x to get x=3. For the first equation 5^3=625 so that also proves x=3.

Sorry if my explanation is a little disorganized if you need more help feel free to ask

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I can do each of the things I asked above.
So, let's change this into vertex form:
$h=-16t^2+36t+4$
$h=(-16t^2+36t)+4$
$h=-16(t^2-2.25t)+4$
$h=-16(t^2-2.25t+1.27-1.27)+4$
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<span>Answers may vary due to rounding

</span>Factored Form:
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Quadratic Formula:
$x = \frac{-b +/- \sqrt{b^2-4(a)(c)}}{2a}$
<span>h = -16t^2 + 36t + 4
</span>a = -16 b = 36 c = 4
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