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3 years ago

Find the perimeter of the following figure

Mathematics

1 answer:

Nastasia [14]3 years ago

4 0

I believe it’s 32.7 ksmakksmakaomwkaimwnsiaklalaowkwnne

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Question is in the picture. Please help

irakobra [83]

BD = AC Given. BD cuts AC in half. That's what bisectors do.

BD = BD Reflexive property of a line (it is always equal to itself).

<ADB = <ADC = 90o

DB is perpendicular to AC Given.

<ADB + <ADC = 180o The two are supplementary.

Each angle = 90o Perpendicular means that one line meets another at 90o

2x = 180

x = 90o

Since each of the enclosed angles = 90, two have two triangles congruent by SAS <<<< Answer

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2 years ago

Use the expression to find the value of the 20th term. A. 24 B. 76 C. 80 D. 84

Oliga [24]

Answer:

Step-by-step explanation:

if its talking about what ones a factor or moltiple of 20 then c if not then i dont know

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3 years ago

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2 years ago

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3 years ago

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

Option A

The solution is:

$x = \pm 2i \sqrt{2}$

Solution:

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$

Thus the solution is found

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2 years ago

Find the perimeter of the following figure​

Find the perimeter of the following figure